AJAX get在Spring中返回404

Question

$("#btn-submit").click(function () {
    var username=document.getElementById("username");
    var password=document.getElementById("password");
    $.ajax({
        url:"login",
        contentType: 'application/json;charset=utf-8',
        dataType: 'text',
        headers: {'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')},
        data: {
            username:username.value,
            password:password.value
        },
        type: 'get',
        success: function (response) {
            if (response=="1") {
                alert(response);
            }
            else alert(response);
        },
        error: function (x, e) {
            console.log(e)
        }
    });
});

LoginController.java

@RequestMapping("/login")
@Controller
public class LoginController {

    @Autowired
    private UserService userService;

    @RequestMapping(value = { "/login" }, method = RequestMethod.GET)
    @ResponseBody
    public int checkValid(@RequestParam("username") String username,@RequestParam("password") String password, HttpServletRequest request, HttpServletResponse response, Locale locale, Model model){
        try {
            if (userService.findByUserName(username).equals(hashPass(password))){
                return 1;
            }
        } catch (NoSuchAlgorithmException e) {
            e.printStackTrace();
            return 0;
        }
        return 0;
    }
    public String hashPass(String pass) throws NoSuchAlgorithmException {
        MessageDigest md = MessageDigest.getInstance("SHA-256");
        byte[] hashInBytes = md.digest(pass.getBytes(StandardCharsets.UTF_8));

        // bytes to hex
        StringBuilder sb = new StringBuilder();
        for (byte b : hashInBytes) {
            sb.append(String.format("%02x", b));
        }
        return sb.toString();
    }
}

spring-config-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>

http://www.springframework.org/schema/jdbc/springframework.org/schema/mvc/springmvc-4.3.xsd http://www.springframework.org/schema/mvc/springmvc-4.3.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/springbeans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/tx

<!-- Enable Annotation based Declarative Transaction Management -->
<tx:annotation-driven proxy-target-class="true"
                      transaction-manager="transactionManager" />

<!-- Creating TransactionManager Bean, since JDBC we are creating of type
  DataSourceTransactionManager -->
<bean id="transactionManager"
      class="org.springframework.jdbc.datasource.DataSourceTransactionManager">
    <property name="dataSource" ref="dataSource" />
</bean>
<bean id="postsDAO" class="com.blog.dao.impl.PostsDAO">
    <property name="jdbcTemplate" ref="jdbcTemplate"/>
</bean>
<bean id="postsService" class="com.blog.service.impl.PostsService">
    <property name="postsDAO" ref="postsDAO"/>
</bean>
<bean id="userDAO" class="com.blog.dao.impl.UserDAO">
    <property name="jdbcTemplate" ref="jdbcTemplate"/>
</bean>
<bean id="userService" class="com.blog.service.impl.UserService">
    <property name="userDAO" ref="userDAO"/>
</bean>

我使用tomcat 9错误：无法加载资源：服务器响应http://localhost:8080/blog_war_explorded/login？username=root&password=root，状态为404（）

Answer 1

请查看您的错误：您正在访问http://localhost:8080/blog_war_explorded/login，但您实际上想访问http://localhost:8080/login。

原因是您将您的URL指定为login而不是/login，因此它是相对于当前“目录”而不是根的。

将代码更改为使用/login应该可以解决此问题：

    $.ajax({
        url: "/login",
        ...
    })

另外，通过GET请求这样做并不是一个好主意--除其他外，密码将以明文形式存储在服务器日志中。您应该改用POST请求。

更新：

而且，您似乎在使用/login的两个请求映射，它们是相互叠加的，因此最终将使用/login/login。查看如何正确使用@requestmapping。