使用JAVA计算字符串的每个段中哪个邮件的数目最多

Question

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String strA = "[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail]," + '\n' +
            "[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail]," + '\n' +
            "[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],";

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关于我的输出的说明：

在第一段-“[e-mail]”是4次，在其他电子邮件中出现的次数最多。

在第二段中--“[e-mail]”是3次，在其他电子邮件中出现的次数最多。

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String strA = "[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail]," + '\n' +
            "[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail]," + '\n' +
            "[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],";
String[] lines = strA.split("\n");
List<Integer> counts = new ArrayList<>();
for (String line : lines) {
    counts.add(new HashSet<String>(Arrays.asList(line.split(","))).size());
}
System.out.println(counts);  // [3, 3, 2]

但如何达到我的目标，输出：4,3,3

请帮帮我.TIA

Answer 1

你就快到了，下面这个建议怎么样：

    String strA = "[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail]," + '\n' +
            "[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail]," + '\n' +
            "[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],";
    String[] lines = strA.split("\n");

    List<HashMap<String, Integer>> segments = new ArrayList<>();
    for(String line: lines){
        HashMap<String, Integer> counts = new HashMap<>();
        segments.add(counts);
        String[] emails = line.split(",");
        for(String email : emails){
            Integer emailCount = counts.containsKey(email) ? counts.get(email) + 1 : 1;

            counts.put(email, emailCount);
        }
    }
    segments.forEach(System.out::println);

输出：

{[e-mail]=4, [e-mail]=3, [e-mail]=3}
{[e-mail]=2, [e-mail]=2, [e-mail]=3}
{[e-mail]=3, [e-mail]=3}

编辑：若要获得所需的输出，可以将最后一行替换为以下一行：

    segments.forEach(segment -> {
       segment.forEach((key, val) -> {
           System.out.print(val + " ");
       });
        System.out.println();
    });

2编辑：

在我现在理解了任务之后，这里有一个更新：d：

public class Application {
public static void main(String[] args){
    String strA = "[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail]," + '\n' +
            "[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail]," + '\n' +
            "[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],[e-mail],";
    String[] lines = strA.split("\n");
    System.out.print("[");
    for(String line: lines){

        Integer count = getMaxCountForSegment(line.split(","));
        System.out.print(count + " ");
    }
    System.out.println("]");
}

public static Integer getMaxCountForSegment(String[] emails){
    HashMap<String, Integer> counts = new HashMap<>();
    for(String email : emails){
       Integer emailCount = counts.containsKey(email) ? counts.get(email) + 1 : 1;
        counts.put(email, emailCount);
    }
    return counts.values().stream().max(Comparator.comparing(Integer::valueOf)).get();
}

输出：

[4, 3, 3]