PHP if else实体都在执行

Question

我是PHP的初学者，我有这样的代码，如果和其他部分都在同一个“运行”中执行。我知道这在逻辑上是不可能的，但这就是我得到的。

以下是我的PHP代码：

<?php

require_once 'create_request_form.php';

$db = new create_request_form();

// json response array
$response = array("error" => FALSE);

if (isset($_POST['rqTitle']) && isset($_POST['rqMname']) && isset($_POST['rqUname']) && isset($_POST['rqBranch']) && isset($_POST['rqText']) && isset($_POST['rqMinPrice']) && isset($_POST['rqMaxPrice']) && isset($_POST['rqImage']) && isset($_POST['rqCategory']) && isset($_POST['rqDateTime'])) {

    // receiving the post params
    $rqTitle = $_POST['rqTitle'];
    $rqMname = $_POST['rqMname'];
    $rqUname = $_POST['rqUname'];
    $rqBranch = $_POST['rqBranch'];
    $rqText = $_POST['rqText'];
    $rqMinPrice = $_POST['rqMinPrice'];
    $rqMaxPrice = $_POST['rqMaxPrice'];
    $rqImage = $_POST['rqImage'];
    $rqCategory = $_POST['rqCategory'];
    $rqDateTime = $_POST['rqDateTime'];


    // check if there is a request  with the same title
    if ($db->checkReqTitle($rqTitle)) {
        // Request already exists
        $response["error"] = TRUE;
        $response["error_msg"] = "Request already exists with the title: " . $rqTitle;
        echo json_encode($response);
    } else {
        // create a new request
        $request = $db->StoreReqInfo($rqTitle, $rqMname, $rqUname, $rqBranch, $rqText, $rqMinPrice, $rqMaxPrice, $rqImage, $rqCategory, $rqDateTime);

        if ($request) {
            // request stored successfully
            $response["error"] = FALSE;
            $response["request"]["rqTitle"] = $request["rqTitle"];
            $response["request"]["rqMname"] = $request["rqMname"];
            $response["request"]["rqUname"] = $request["rqUname"];
            $response["request"]["rqBranch"] = $request["rqBranch"];
            $response["request"]["rqText"] = $request["rqText"];
            $response["request"]["rqMinPrice"] = $request["rqMinPrice"];
            $response["request"]["rqMaxPrice"] = $request["rqMaxPrice"];
            $response["request"]["rqImage"] = $request["rqImage"];
            $response["request"]["rqCategory"] = $request["rqCategory"];
            $response["request"]["rqDateTime"] = $request["rqDateTime"];

            echo json_encode($response);

        } else {
            // request failed to store
            $response["error"] = TRUE; 
            $response["error_msg"] = "An error occurred while creating the request. Please try again.";
            echo json_encode($response);
        }
     }
} else {
    $response["error"] = TRUE;
    $response["error_msg"] = "Required parameter is missing!";
    echo json_encode($response);
}
?>

所需的行为（在数据库中存储数据）都执行得很好，但是我得到的$响应是当请求标题已经存在时分配给我的错误字符串，而不是存储请求的JSON格式化数组（如果执行和其他机构，但是我得到如果身体作为反应的结果）。

我还使用Galaxy Note 4进行测试，它只显示一条空白的Toast消息，不会启动intent（不会移动到主屏幕）。

到目前为止，唯一可能的解释是脚本被执行了两次，但是我找不到第二次调用它的地方。

这是java代码，负责将带有所需参数的请求发送到上面的php脚本。

 private void storeRequest(final String rTitle, final String rMname, final String rUname,
                          final String rBranch, final String rText,  final String rMinPrice,
                          final String rMaxPrice, final String imagePath, final String rCategory) {

    // Tag used to cancel the request
    String cancel_req_tag = "request";

    //A progress dialog message to let the user know they are being registered
    progressDialog.setMessage("Please wait while we add your request...");
    showDialog();

    //creating a StringRequest to send the registration info to the script
    // at the server for processing
    StringRequest strReq = new StringRequest(Request.Method.POST,
            URL_FOR_REQUEST, new Response.Listener<String>() {

        @Override
        public void onResponse(String response) {
            Log.d(TAG, "Request Response: " + response.toString());
            hideDialog();

            try { //json objects must be surrounded by try catch statement
                JSONObject jObj = new JSONObject(response);
                boolean error = jObj.getBoolean("error");

                if (!error) { // error is set to false, meaning no error

                    // Launch home activity
                    Intent intent = new Intent(CreateRequestActivity.this, HomeActivity.class);
                    startActivity(intent);
                    finish();

                } else {

                    String errorMsg = jObj.getString("error_msg");
                    Toast.makeText(CreateRequestActivity.this, errorMsg, Toast.LENGTH_LONG).show();
                }



            } catch (JSONException e) {
                e.printStackTrace();
            }

        }
    }, new Response.ErrorListener() {

        @Override
        public void onErrorResponse(VolleyError error) {
            Log.e(TAG, "Error: " + error.getMessage());
            Toast.makeText(CreateRequestActivity.this,
                    error.getMessage(), Toast.LENGTH_LONG).show();
            hideDialog();
        }
    }) {
        @Override
        protected Map<String, String> getParams() {
            // Posting params to register url
            Map<String, String> params = new HashMap<String, String>();
            params.put("rqTitle", rTitle);
            params.put("rqText", rText);
            params.put("rqMname", rMname);
            params.put("rqUname", rUname);
            params.put("rqBranch", rBranch);
            params.put("rqMinPrice", rMinPrice);
            params.put("rqMaxPrice", rMaxPrice);
            params.put("rqImage", imagePath);
            params.put("rqCategory", rCategory);
            params.put("rqDateTime", DateFormat.getDateTimeInstance().format(new Date()));
            return params;
        }
    };
    // Adding request to request queue
    AppSingleton.getInstance(getApplicationContext()).addToRequestQueue(strReq, cancel_req_tag);
}

有什么想法吗？

提前感谢！

Answer 1

因此，问题源于Java代码，而不是PHP（糟糕的PHP；P）。更准确地说，截击请求存在请求超时问题，特别是在使用POST方法发送请求时。

所以对我来说有效的是在将请求添加到队列之前添加这一行：

strReq.setRetryPolicy(new DefaultRetryPolicy(0, -1, 0));

*用您的请求名称替换strReq。基本上，这条线的作用是防止截击在第一个请求花费太长时间时发送重复的请求。

原著

DefaultRetryPolicy.class的hasAttemptRemning（）类如下所示：

受保护的布尔值hasAttemptRemning（）{返回this. mMONtRetryCount

我用螺丝钉把它修好了

要求setRetryPolicy（新的DefaultRetryPolicy（0，-1,0）；

来源：当重试策略设置为0时，Android Volley向服务器发出2个请求