Java新手错误Android编程发送消息方法

Question

于是我用Java 7开始了一些安卓编程。我有Eclipse Juno（我想是4.2）。

问题是它给了我一个错误“multiple markers at this line-Syntax error on token”）“,；expected-Syntax error on token”）“,；expected

在带有sendMessage方法的行上。代码如下：

public class MainActivity extends ActionBarActivity {


int counter;
Button login; 
EditText username, password;
String success;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    counter = 0;

    username = (EditText)findViewById(R.id.getEmail);
    password = (EditText)findViewById(R.id.getPassword);        

    login.setOnClickListener(new View.OnClickListener() {       
        public void onClick (View v) {
            if(username.getText().toString().equals("admin") && password.getText().toString().equals("admin")){
                success = "Successful";
                counter = 0;
                public void sendMessage (View view){
                    Intent intent = new Intent("com.example.linked1n.SCREENAFTLOG");
                    startActivity(intent);
                };
            } else {
                    counter++;
                    login.setText("Unsuccessful. Try again. " + 3-counter + " tries left.");
            }   
        }   
    });



}

我还没有找到一个解决方案，我完全按照教程告诉我的做了。我尝试了三次清理项目并重新启动Eclipse/Computer,但没有工作。

Answer 1

您在onclick中的调用方法是错误的，所以请尝试下面的方法：-

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    counter = 0;

    username = (EditText)findViewById(R.id.getEmail);
    password = (EditText)findViewById(R.id.getPassword);        

    login.setOnClickListener(new View.OnClickListener() {       
        public void onClick (View v) {
            if(username.getText().toString().equals("admin") && password.getText().toString().equals("admin")){
                success = "Successful";
                counter = 0;
               sendMessage(v);
            } else {
                    counter++;
                    login.setText("Unsuccessful. Try again. " + 3-counter + " tries left.");
            }   
        }   
    });

 public void sendMessage (View view){
                        Intent intent = new Intent("com.example.linked1n.SCREENAFTLOG");
                        startActivity(intent);
                    }