错误：student类中的构造函数student不能应用于给定类型；超级（姓名、注册）；

Question

我一开始就宣布了超级权利。但它仍然显示了错误，即它不是。此外，父类中的构造函数具有与“super（）”中的构造函数相同的参数。它仍然说参数不匹配

 import java.io.*;
    import java.util.Scanner;
    
     class student
    {
      public String name;
      public int enroll;
    
      public void student(String name, int enroll)
      {
        this.name=name;
        this.enroll=enroll;
      }
    }
    class Science extends student
    {
      int phy;
      int chem;
      int maths;
      public void Science(String name, int enroll, int phy, int chem, int maths)
      {
        super(name,enroll);
        this.phy=phy;
        this.chem=chem;
        this.maths=maths;
      }
    }
    class Arts extends student
    {
      int eng;
      int hist;
      int eco;
      public void Arts(String name, int enroll, int eng, int hist, int eco)
      {
        super(name,enroll);
        this.eng=eng;
        this.hist=hist;
        this.eco=eco;
      }
      
    }
    public class asd
    {
      //enter code here
      public static void main(String[] args)  throws IOException
      {
        //enter code here
       } 
      
    }

Answer 1

正如注释中指出的，您需要从构造函数中删除void，因为它们没有任何显式返回类型。您可以检查这个答案，找出构造函数不返回值的原因。

当前的构造函数如下所示：

java prettyprint-override">public void student(String name, int enroll)
{
    this.name=name;
    this.enroll=enroll;
}

应该是这样的,而且类名应该按照标准的Java约定以大写字母开头：

class Student {

  public Student(String name, int enroll)
  {
    this.name=name;
    this.enroll=enroll;
  }