如何解析函数datediff（未知，时间戳没有时区，时间戳没有时区）不存在

Question

SELECT "reviewedAt", "createdAt", DATEDIFF('hour', "createdAt"::timestamp, "reviewedAt"::timestamp) as hours_approved from "yadda$prod"."Application" 

错误[42883]错误：函数datediff（未知，没有时区的时间戳，没有时区的时间戳）不存在提示：没有函数与给定的名称和参数类型匹配。您可能需要添加显式类型转换。职位：36

Answer 1

还有一个解决方案：

SELECT 
    "reviewedAt",
    "createdAt",
    (EXTRACT(EPOCH FROM "reviewedAt"::timestamp - "createdAt"::timestamp)/3600)::int2 AS hours_approved
FROM "yadda$prod"."Application";

Answer 2

试试这个：

SELECT 
"reviewedAt",
"createdAt",
DATE_PART('day', "reviewedAt"::timestamp - "createdAt"::timestamp) * 24 + DATE_PART('hour', "reviewedAt"::timestamp - "createdAt"::timestamp) AS hours_approved 
FROM "yadda$prod"."Application"