Linux套接字只接收第一块数据

Question

我有两个程序，一个是服务器，一个只听，另一个是客户端。我发送100字节的数据，每个数据块64字节。我将获得64字节的第一块数据，但随后我的服务器退出，因为它无法获取其他数据。我的客户正在发送所有数据。

void ServerLinux::Receive(){

    int sock = 0;
    struct sockaddr_in server;
    char buffer[this->packageLength];

    if ((sock = socket(PF_INET, SOCK_STREAM, IPPROTO_TCP)) < 0) {
        this->Die("Failed to create socket");
    }

    memset(&server, 0, sizeof(server));
    server.sin_family = AF_INET;
    server.sin_addr.s_addr = htonl(INADDR_ANY);
    server.sin_port = htons(this->port);

    if(bind(sock, (struct sockaddr *) &server, sizeof(server)) < 0){
        this->Die("Failed to bind the server socket");
    }
    if(listen(sock, 1) < 0){
        this->Die("Failed to listen on server socket");
    }

    int clientSocket = 0;
    struct sockaddr_in client;
    socklen_t size = sizeof(client);
    if((clientSocket = accept(sock, (struct sockaddr *) &client, &size)) < 0){
        this->Die("Failed to accept client");
    }

    int received = -1;

    //This is fine data is recived
    if((received = recv(clientSocket, buffer, this->packageLength,0)) < 0){
        this->Die("Failed to receive initial bytes from client");
    }
    std::cout << "Received!" << std::endl;

    //Data is not received in this while loop
    while(received > 0){
        if((received = recv(sock, buffer, this->packageLength,0)) < 0){
            this->Die("Failed to receive additional bytes frin client");
        }
        std::cout << "Received!" << std::endl;
    }
}

Answer 1

你为什么不对 recv 使用相同的参数？

作品： recv（clientSocket， buffer， this-

recv（sock，buffer，this）不起作用-

将袜子更改为客户端套接字。