列出用户输入数字的倍数

Question

任务是“编写一个程序，为用户输入的整数显示用户指示的倍数。”

我想我不需要一个完全直接的答案（尽管我确实想知道要使用的方法/公式），因为我想把这个作为一个学习经验，以便自己完成任务并从中学习。我真的想知道的过程和使用的方法，以及找到一个公式。：

我真的不确定如何编写一个代码，显示一个用户输入的整数的用户输入的数字。最难的部分似乎是编写循环公式。不知道从哪里开始。

到目前为止，我已经：

import java.util.Scanner;

public class MultipleLooping
{
   public static void main(String[] args)
   {   
      Scanner keyboard = new Scanner(System.in); 

\\just stuff to base my code off of

      int integer;
      int numberMultiples;

      System.out.println("Enter an integer: ");

      integer = keyboard.nextInt();

      System.out.println("How many multiples of " + integer + " would you like to know?");
         numberMultiples = keyboard.nextInt();

      System.out.println("Listing the first " + numberMultiples + " multiples of " + integer + ": ");

\\pretty much everything from here on out.. I'm not sure what to really do.
      int n = integer;
      int result = (integer * (numberMultiples));
      while (result > 0){}

      System.out.print(result);
   }
} \\at the moment this code doesn't seem to have any running errors

我真的不确定如何编写一个代码，显示一个用户输入的整数的用户输入的数字。最难的部分似乎是编写循环公式。不知道从哪里开始。

新问题我也需要循环我的程序。（通过先向用户提出一个问题。）Mines不起作用，因为它只循环整数循环，不让我输入yes/no。导入java.util.scanner；

public class MultipleLoops
{
    public static void main(String[] args)
    {

       Scanner keyboard = new Scanner(System.in);
       int integer, numberMultiples;
       String repeat = "yes";

       while (repeat != "no")
       {
         System.out.println("Enter an integer: ");
         integer = keyboard.nextInt();

         System.out.println("How many multiples of " + integer + " would you like to know?");
         numberMultiples = keyboard.nextInt();

         System.out.println("Listing the first " + numberMultiples + " multiples of " + integer + ": ");

         for (int i=1; i<=numberMultiples; i++){
         System.out.println(integer + " * " + i + "   =  " + i*integer );
         }


         System.out.println("Would you like to do this again? Enter yes or no: ");
         repeat = keyboard.nextLine();


   }  

} 

}

Answer 1

好的，所以你需要先了解问题，知道如何解决它

x = First input
n = Second input 

你需要计算x的n倍数，例如x=3和n=10要计算3的10倍数，我们需要做的是：

  1st multiple = x*1
  2nd multiple = x*2
  3rd multiple = x*3
  ...
  n   multiple = x*n

您可以注意到这些操作可以被一个for循环替换（注意每一行的第一个和最后一个字符，它可以是您的循环的索引）

返回Java：）

for (int i=1; i<=numberMultiples; i++){
    System.out.println("Listing multiple N# " + i + "   =  "+ i*integer );
 }

用以下代码替换您的代码并尝试此代码：

import java.util.Scanner;

public class MultipleLooping{
    public static void main(String[] args){
        Scanner keyboard = new Scanner(System.in);
        int integer,numberMultiples;

        System.out.println("Enter an integer: ");
        integer = keyboard.nextInt();

        System.out.println("How many multiples of " + integer + " would you like to know?");
        numberMultiples = keyboard.nextInt();

        for (int i=1; i<=numberMultiples; i++){
            System.out.println("Listing multiple N# " + i + "   =  "+ i*integer );
        }
    }
}


Enter an integer: 
3
How many multiples of 3 would you like to know?
7
Listing multiple N# 1   =  3
Listing multiple N# 2   =  6
Listing multiple N# 3   =  9
Listing multiple N# 4   =  12
Listing multiple N# 5   =  15
Listing multiple N# 6   =  18
Listing multiple N# 7   =  21