使用更好的条件缩短Python中的长if-else检查

Question

我正在写一个Python程序，在这里我需要一个if-ther案例来选择1和9之间的一个数字，每个数字都被分配给一个类。关于如何缩短这段代码的任何建议？

import randint

variable1 = randint(1, 9)
if variable1 >= 9:
  print ("Your class is Tiefling") 
else: 
  if variable1 >= 8: 
    print ("Your class is Half-Orc") 
  else: 
    if variable1 >= 7: 
      print ("Your class is Half-Elf") 
    else:
      if variable1 >= 6: 
        print ("Your class is Gnome")
      else:
        if variable1 >= 5:
          print ("Your class is Dragonborn") 
         else: 
           if variable1 >= 4:
            print ("Your class is Human") 
          else:
            if variable1 >= 3:
              print ("Your class is Halfling") 
            else:
              if variable1 >= 2: 
                print ("Your class is Elf") 
              else:
                if variable1 >= 1:
                  print ("Your class is Dwarf")

Answer 1

使用字典的不完整版本：

val_msg = {3: 'Your class is Halfling',
           2: 'Your class is Elf',
           1: 'Your class is Dwarf'}

from random import randint

variable1 = randint(1, 3)
print(val_msg[variable1])

请注意，randint生成我用作字典键的整数。

如果您需要做更复杂的事情，您可以将函数放入字典并调用它们（当然，您也可以使用这里基于列表的解决方案执行相同的操作）：

def do_halfling_stuff():
    print('Your class is Halfling')
def do_elf_stuff():
    print('Your class is Elf')
def do_dwarf_stuff():
    print('Your class is Dwarf')

val_func = {3: do_halfling_stuff,
            2: do_elf_stuff,
            1: do_dwarf_stuff}


variable1 = randint(1, 3)
func = val_func[variable1]
func()

Answer 2

我希望这有帮助！

import random 
classList = ['Dwarf','Elf','Halfling','Human','Dragonborn','Gnome','Half-Elf','Half-Orc','Tiefling'] 
print 'Your class is ' + random.choice(classList)

Answer 3

使用列表的示例

import random

classes = ['Tiefling', 'Half-Orc', 'Half-Elf', '...']

print('Your class is ' + classes[random.randrange(len(classes))])

根据亚历克西斯的评论编辑的。