如何在改型2 Kotlin中发送post参数中的任何类型的文件？

Question

让我分享一些我的代码，我已经实现发送图像文件在请求。

@Multipart
@POST("api/order/order_create")
fun createOrder(
    @Header("Authorization") authorization: String?,
    @Part("category_id") categoryId: RequestBody?,
    @Part("size") size: RequestBody?,
    @Part("narration") narration: RequestBody?,
    @Part("ref_picture") file: RequestBody?
): Call<OrderCreateResponse>

var fbody = RequestBody.create(MediaType.parse("image/*"), imageFile)
var size = RequestBody.create(MediaType.parse("text/plain"), et_custom_order_size.text.toString())
var catId = RequestBody.create(MediaType.parse("text/plain"), selectedID.toString())
var narration = RequestBody.create(MediaType.parse("text/plain"),et_custom_order_narration.text.toString())

val orderCreateAPI = apiService!!.createOrder(complexPreferences?.getPref("token", null), catId,size,narration,fbody)

imageFile = File(Global.getRealPathFromURI(activity!!, imageUri!!))

fun getRealPathFromURI(context: Context, contentUri: Uri): String {
        var cursor: Cursor? = null
        try {
            val proj = arrayOf(MediaStore.Images.Media.DATA)
            cursor = context.contentResolver.query(contentUri, proj, null, null, null)
            val column_index = cursor!!.getColumnIndexOrThrow(MediaStore.Images.Media.DATA)
            cursor.moveToFirst()
            return cursor.getString(column_index)
        } catch (e: Exception) {
            Log.e(TAG, "getRealPathFromURI Exception : " + e.toString())
            return ""
        } finally {
            if (cursor != null) {
                cursor.close()
            }
        }
    }

通过以上方式发送图像，我无法发送它！请用同样的指导我。提前谢了。

Answer 1

@Multipart
@POST("register")
Observable<SignInResponse> signUp(@Part("name") RequestBody name, @Part MultipartBody.Part fileToUpload);

然后将图像文件作为multipartbody.part变量传递

// image as file
    var body: MultipartBody.Part? = null
    if (!profileImagePath.isNullOrBlank()) {
        val file = File(profileImagePath)
        val inputStream = contentResolver.openInputStream(Uri.fromFile(file))
        val requestFile = RequestBody.create(MediaType.parse("image/jpeg"), getBytes(inputStream))
        body = MultipartBody.Part.createFormData("image", file.name, requestFile)
        Log.d("nama file e cuk", file.name)
    }

您可以使RequestBody var的最后一件事

RequestBody.create(MediaType.parse("text/plain"), user_full_name)

最后发送请求：）