如何在Spring MVC中通过返回自定义错误页来全局处理404异常？

Question

HTTP Status 404 -

type Status report

message

description The requested resource is not available.

1)

@Controller   //for class
@ResponseStatus(value = HttpStatus.NOT_FOUND) //for method

2)
 @Controller   //for class
 @ResponseStatus(value = HttpStatus.NOT_FOUND) //for method
 @ExceptionHandler(ResourceNotFoundException.class) //for method

3)

@ControllerAdvice //for class
@ResponseStatus(value = HttpStatus.NOT_FOUND) //for method

3)

@ControllerAdvice //for class
@ResponseStatus(HttpStatus.NOT_FOUND) //for method

4)
 @ControllerAdvice   //for class
 @ResponseStatus(value = HttpStatus.NOT_FOUND) //for method
 @ExceptionHandler(ResourceNotFoundException.class) //for method

@ControllerAdvice
public class GlobalExceptionHandler {
    @ResponseStatus(value = HttpStatus.NOT_FOUND)
    public String handleBadRequest(Exception exception) {
          return "error404";
    }
}

Answer 1

DispatcherServlet如果没有找到处理请求的处理程序，则默认情况下不会引发异常。因此，您需要显式激活它，如下所示：

在web.xml中：

<servlet>
    <servlet-name>mvc-dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>throwExceptionIfNoHandlerFound</param-name>
        <param-value>true</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

如果使用基于注释的配置：

dispatcherServlet.setThrowExceptionIfNoHandlerFound(true);

@ExceptionHandler
@ResponseStatus(HttpStatus.NOT_FOUND)
public String handleExceptiond(NoHandlerFoundException ex) {
    return "errorPage";
}