我的一个方法使用了在另一个方法中返回的变量。我无法获得打印或计算的第二种方法

Question

一家油漆公司确定，每115平方英尺的墙面空间，将需要一加仑的油漆和8小时的人工。这家公司的人工费为每小时18美元。编写一个程序，允许用户输入需要粉刷的房间数量和每加仑油漆的价格。它还应该要求每个房间有平方英尺的墙壁空间。程序应该有返回以下数据的方法:•所需油漆的加仑数•所需人工小时数•油漆成本•人工费用•油漆作业的总成本，然后它应该在屏幕上显示这些数据。

我还没有处理这个问题的劳工部分，但是由于paintNeeded变量，我无法将costOfPaint（）打印出来。

我尝试将costOfPaint方法中的语句写入main方法中，它起作用了。但这没有帮助，因为我需要这样做的方法。我知道我的问题与paintNeeded变量有关，我只是不确定如何解决这个问题。

公共类Main{

public static double paintRequired(double totalSquareFeet){

    double paintNeeded = totalSquareFeet / 115;
    return paintNeeded;

                                                          }

public static double costOfPaint(double paintNeeded, double costOfPaint){
    double paintCost = paintNeeded * costOfPaint;
    return paintCost;
                                                    }


public static void main(String[] args){
    double costOfPaint = 0;
    int totalSquareFeet = 0;
    double paintNeeded = 0;

    Scanner getUserInput = new Scanner(System.in);

    System.out.println("what is the cost of the paint per gallon");
        costOfPaint = getUserInput.nextDouble();
    System.out.println("How many rooms do you need painted");
        int rooms = getUserInput.nextInt();
            for(int i = 1; i <= rooms; i++){
                System.out.println("how many square feet are in room:" + i);
                int roomSquareFeet = getUserInput.nextInt();
                totalSquareFeet = roomSquareFeet + totalSquareFeet;
                                           }

    System.out.println("the amount of paint needed:" + paintRequired(totalSquareFeet) + "gallons");
    System.out.println("the cost of the paint will be: " + costOfPaint(paintNeeded, costOfPaint));

}

}

我的costOfPaint一直都是0。

Answer 1

您不更改PaintNeeded。总是0。

paintNeeded = paintRequired(totalSquareFeet);

System.out.println("the amount of paint needed: " + paintNeeded + " gallons");
System.out.println("the cost of the paint will be: " + costOfPaint(paintNeeded, costOfPaint));