在Spring Boot中未自动创建数据库

Question

我有一个 Spring 引导 API，它使用 jpa 和 postgresql，并在我运行应用程序时自动创建表。

但出现以下错误消息：

> 
Caused by: org.hibernate.AnnotationException: mappedBy reference an unknown target entity property: com.globalsys.apicep.model.Cep.Cidade in com.globalsys.apicep.model.Cidade.ceps
    at org.hibernate.cfg.annotations.CollectionBinder.bindStarToManySecondPass(CollectionBinder.java:844) ~[hibernate-core-5.4.23.Final.jar:5.4.23.Final]
    at org.hibernate.cfg.annotations.CollectionBinder$1.secondPass(CollectionBinder.java:795) ~[hibernate-core-5.4.23.Final.jar:5.4.23.Final]
    at org.hibernate.cfg.CollectionSecondPass.doSecondPass(CollectionSecondPass.java:53) ~[hibernate-core-5.4.23.Final.jar:5.4.23.Final]
    at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processSecondPasses(InFlightMetadataCollectorImpl.java:1693) ~[hibernate-core-5.4.23.Final.jar:5.4.23.Final]
    at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processSecondPasses(InFlightMetadataCollectorImpl.java:1661) ~[hibernate-core-5.4.23.Final.jar:5.4.23.Final]
    at org.hibernate.boot.model.process.spi.MetadataBuildingProcess.complete(MetadataBuildingProcess.java:286) ~[hibernate-core-5.4.23.Final.jar:5.4.23.Final]
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.metadata(EntityManagerFactoryBuilderImpl.java:1224) ~[hibernate-core-5.4.23.Final.jar:5.4.23.Final]
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:1255) ~[hibernate-core-5.4.23.Final.jar:5.4.23.Final]
    at org.springframework.orm.jpa.vendor.SpringHibernateJpaPersistenceProvider.createContainerEntityManagerFactory(SpringHibernateJpaPersistenceProvider.java:58) ~[spring-orm-5.3.1.jar:5.3.1]
    at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:365) ~[spring-orm-5.3.1.jar:5.3.1]
    at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.buildNativeEntityManagerFactory(AbstractEntityManagerFactoryBean.java:409) ~[spring-orm-5.3.1.jar:5.3.1]
    at java.base/java.util.concurrent.FutureTask.run(FutureTask.java:264) ~[na:na]
    at java.base/java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1130) ~[na:na]
    at java.base/java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:630) ~[na:na]
    at java.base/java.lang.Thread.run(Thread.java:832) ~[na:na]

这是我的应用程序。属性

server.port=8080
spring.datasource.url=jdbc:postgresql://localhost:5432/dbcep
spring.datasource.driverClassName=org.postgresql.Driver
spring.datasource.username=postgres
spring.datasource.password=romulo
spring.jpa.open-in-view=true
spring.jpa.hibernate.ddl-auto=update
spring.jpa.properties.hibernate.dialect=org.hibernate.dialect.PostgreSQLDialect
spring.jpa.properties.hibernate.show_sql=true
spring.jpa.properties.hibernate.temp.use_jdbc_metadata_defaults=false

Answer 1

好消息！问题是mapped by属性中的一个引用，我一开始觉得没什么问题。

在 OneToMany 中，我以这种方式引用了表格本身！

@OneToMany(mappedBy = "Cidade", cascade = CascadeType.ALL)
    private List<Cep> ceps;

事实证明，您不能参考表格本身！相反，您需要引用关系另一方的财产，即关系的所有者！

 @ManyToOne
    private Cidade cidade;

在Cep类模型中！