JavaScript排序基于属性数组对象数组

Question

例如，我有以下数据集：

const order = [
  { key: "job", direction: "ascending" },
  { key: "age", direction: "descending" },
];

const records = [
  { name: "christian", age: 40, job: "developer" },
  { name: "andrew", age: 48, job: "developer" },
  { name: "elisabeth", age: 31, job: "floor manager" },
  { name: "oscar", age: 61, job: "floor manager" },
  { name: "gisela", age: 51, job: "area manager" },
  { name: "buffy", age: 27, job: "trainee" },
  { name: "carl", age: 23, job: "trainee" },
];

我需要根据order数组中的条件对records数组进行排序。我最终得出了这样的解决方案：

const sorted = records.sort(
  (recordA, recordB) =>
    recordA.job.localeCompare(recordB.job) || recordA.age - recordB.age
);

但我无法理解如何使用order数组而不是硬编码的job和age属性。order数组可以有许多属性。

Answer 1

只需循环访问订单数据并进行比较：

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let order = [{ key: "job", direction: "ascending" }, { key: "age", direction: "descending" }];
let records = [{ name: "christian", age: 40, job: "developer" }, { name: "andrew", age: 48, job: "developer" }, { name: "elisabeth", age: 31, job: "floor manager" }, { name: "oscar", age: 61, job: "floor manager" }, { name: "gisela", age: 51, job: "area manager" }, { name: "buffy", age: 27, job: "trainee" }, { name: "carl", age: 23, job: "trainee" }];

records.sort(function (a, b) {
    for (let {key, direction} of order) {
        if (a[key] !== b[key]) return (direction[0] === "a") === (a[key] < b[key]) ? -1 : 1;
    }
    return 0;
});

console.log(records);

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Answer 2

您可以对通缉令执行一个闭包，并检查值是否有限，然后返回delta或将值作为字符串处理。

内部排序函数只要返回值为假值就迭代，并将该值作为返回值进行排序。

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const
    sortBy = order => (a, b) => {
        let r;
        order.some(({ key, direction }) => r = (isFinite(a[key]) && isFinite(b[key])
            ? a[key] - b[key]
            : a[key].toString().localeCompare(b[key])        
        ) * (direction === 'ascending' || -1))
        return r;
    },
    records = [{ name: "christian", age: 40, job: "developer" }, { name: "andrew", age: 48, job: "developer" }, { name: "elisabeth", age: 31, job: "floor manager" }, { name: "oscar", age: 61, job: "floor manager" }, { name: "gisela", age: 51, job: "area manager" }, { name: "buffy", age: 27, job: "trainee" }, { name: "carl", age: 23, job: "trainee" }],
    order = [{ key: "job", direction: "ascending" }, { key: "age", direction: "descending" }];

console.log(records.sort(sortBy(order)));

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