如何将部分请求发送到另一个url

Question

我有一个Web服务，它使用Spring Rest Controller（使用Netty而不是Apache Tomcat）处理GET/POST/PUT HTTP请求。我希望过滤我服务中的所有请求，当请求配置了特定的标头时，我希望将此特定请求发送到一个完全不同的URL，同时将响应返回到发送原始请求的相同实体。

这是我的代码：

@Component
public class MyWebFilter implements WebFilter {

    @Autowired
    private SomeService someService;
    private final Logger log = LoggerFactory.getLogger(MyWebFilter.class);

    @Override
    public Mono<Void> filter(ServerWebExchange serverWebExchange, WebFilterChain webFilterChain) {
        HttpHeaders headers = serverWebExchange.getRequest().getHeaders();
        if (headers.containsKey("someHeader")) {
            if (someService.askSomething(Objects.requireNonNull(headers.get("someHeader")))) {
                URI originalUri = serverWebExchange.getRequest().getURI();
                log.info("Redirecting request with URI {} to some service", originalUri.getPath());
                try {
                    URI someUri = new URI("http",
                            originalUri.getUserInfo(),
                            someService.getHost(),
                            someService.getPort(),
                            originalUri.getPath(),
                            originalUri.getQuery(),
                            originalUri.getFragment());
                    ServerHttpRequest newRequest =  serverWebExchange.getRequest().mutate().uri(someUri).build();
                    ServerWebExchange newExchange = serverWebExchange.mutate().request(newRequest).build();
                    return webFilterChain.filter(newExchange);
                } catch (URISyntaxException e) {
                    throw new IllegalStateException(e.getMessage(), e);
                }
            }
        }
        return webFilterChain.filter(serverWebExchange);
    }
}

在这个实现中，请求只是传递给我的普通rest控制器，而不会到达其他服务。我错过了什么？

Answer 1

您应该添加@Order并指定正确的顺序，然后设置debug=true以查看过滤器的执行情况。另请参见spring webflux webfilters