RegEx匹配器总是返回false

Question

我试图解析这样的字符串；

/^/^这是一个大/*这是一个粗体文本/-这是删除。我需要$/^和$之间的文本

在regexr和java regex tester上对regex进行了测试，并显示了它的工作状态。

 public static final String bold = "/\\/\\*(.*?)\\|/g";
    public static final String strike = "/\\/\\-(.*?)\\|/g";
    public static final String big = "/\\/\\^(.*?)\\|/g"; 


    String input = "/^/^this is a big|/*this is a bold text|/-this is strike through|";

    SpannableStringBuilder str = new SpannableStringBuilder(input.trim());
    Pattern pattern = big;
    Matcher matcher = pattern.matcher(str.toString());

            while (matcher.find()) {
                  str.setSpan(new RelativeSizeSpan((1.25f)),
                        matcher.start(), matcher.end(),
                        SPAN_INCLUSIVE_INCLUSIVE);
                //input.replace(matcher.group(1),"");
            }

Pattern pattern = Pattern.compile(big);

Answer 1

    Pattern pattern = Pattern.compile("/\\^(.*?)\\|");

    String input = "/^/^this is a big|/*this is a bold text|/-this is strike through|";
    Matcher matcher = pattern.matcher(input);
    while (matcher.find()) {
        System.out.println("Found: " + matcher.group(1));
    }
    System.out.println("That’s all, folks");

输出为：

Found: /^this is a big
That’s all, folks

如果要删除/^和之间的文本，请使用matcher.appendreplacement()文档中给出的习惯用法：

    StringBuilder sb = new StringBuilder();
    while (matcher.find()) {
        matcher.appendReplacement(sb, "/^|");
    }
    matcher.appendTail(sb);
    System.out.println(sb.toString());  

/^|/*this is a bold text|/-this is strike through|

为什么你的代码不起作用？

    String patternString = "is";

    Pattern pattern = Pattern.compile(patternString);