如何检查一个数组是否包含可以在另一个数组中找到的元素并存储它们的值

Question

我如何检查下面的两个对象是否有匹配的元素？如果它们有匹配的元素..我希望将匹配的元素存储在一个名为var storeHere=[]的空变量中。

var one = ["2021-02-25", "2021-02-24", "2021-02-23", "2021-02-22", "2021-02-21", "2021-03-02", "2021-02-11", "2021-02-10"];
var two = ["2021-02-25", "2021-02-25", "2021-02-23"];

var storeHere = [];

到目前为止，我设法匹配了这两个对象，如果匹配，则得到一个true或一个false，但我还希望将匹配值存储在一个emtpy变量中。

var one = ["2021-02-25", "2021-02-24", "2021-02-23", "2021-02-22", "2021-02-21", "2021-03-02", "2021-02-11", "2021-02-10"];
var two = ["2021-02-25", "2021-02-25", "2021-02-23"];

function ex (alldates, selected) {
    return selected.some(function (v) {
        return alldates.indexOf(v) >= 0;
    });
};
    ex(one, two);
  

Answer 1

你能做到的

var one = ["2021-02-25", "2021-02-24", "2021-02-23", "2021-02-22", "2021-02-21", "2021-03-02", "2021-02-11", "2021-02-10"];
var two = ["2021-02-25", "2021-02-25", "2021-02-23"]; 
var storeHere = [];


one.forEach(date => {
   if(two.includes(date)) {
       storeHere.push(date);
   }
}

Answer 2

你有几个选择

您可以使用array.filter:

const one = [
    "2021-02-25",
    "2021-02-24",
    "2021-02-23",
    "2021-02-22",
    "2021-02-21",
    "2021-03-02",
    "2021-02-11",
    "2021-02-10",
];

const two = [
    "2021-02-25",
    "2021-02-25",
    "2021-02-23",
];

// If an element is in two, include it. Otherwise, exclude it.
const storeHere = one.filter((date) => two.includes(date))

console.log(storeHere) // [ '2021-02-25', '2021-02-23' ]

或者您可以使用set.hasES6集：

const one = [
    "2021-02-25",
    "2021-02-24",
    "2021-02-23",
    "2021-02-22",
    "2021-02-21",
    "2021-03-02",
    "2021-02-11",
    "2021-02-10",
];

const two = new Set([
    "2021-02-25",
    "2021-02-25",
    "2021-02-23",
]);

// If an element is in two, include it. Otherwise, exclude it.
const storeHere = one.filter((date) => two.has(date))

console.log(storeHere) // [ '2021-02-25', '2021-02-23' ]

集合的优点是它更快，因为它只包含唯一的元素（如果存在任何重复的元素）。然而，差别可能很小，因为这两种解决方案基本上是同一件事。