解析复合csv的方法表现得很奇怪

Question

这个问题与我之前发布的一个问题有关：

在java中解析拆分的csv文件

它与我试图编写的一个方法有关，该方法能够将csv文件拆分为几个不同的数组列表，其中每个列表的数据由一个注释分隔，该注释由“%”表示

这是我写的代码：

ArrayList<ArrayList<int[]>> parseValues(Scanner input, int size)
{
    ArrayList<ArrayList<int[]>> output = new ArrayList<ArrayList<int[]>>();
    boolean state = false;
    boolean lastState = false;
    int count = 0;
    int i = -1;

    System.out.println();

    while (input.hasNextLine())
    {
        String temp = input.nextLine();

        if (temp.startsWith("%"))
            state = false;
        else
            state = true;

        if (state != lastState)
        {
            count++;
        }

        if (count % 2 == 0)
        {
            output.add(new ArrayList<int[]>());
            System.out.println("====new list====");
            i++;
        }

        lastState = state;

        if (!temp.startsWith("%"))
        {
            int j = 0;
            int[] values = new int[size];

            for (String value: temp.split(","))
            {
                try
                {
                    values[j] = Integer.parseInt(value);
                }
                catch (NumberFormatException e)
                {
                    values[j] = 0;
                }

                j++;
            }

            output.get(i).add(values);
        }
        System.out.println("count = " + count + "  count%2 = " + 
                (count%2) + "  state = " + state + "  lastState = " + 
                lastState +"  output.size() = " + output.size() + 
                "  output[i].size() = " + output.get(i).size());
    }

    return output;
}

(println语句都只是为了调试)

当我将以下文件输入算法时：

% into ArrayList<Integer> list1
3,4,5,2,2,3
5,6,3,2,4,5
3,2,3,4,5,6
2,3,4,5,1,3
4,3,5,4,3,2
4,4,3,4,5,4
% 
% the values below here should go
% into ArrayList<Integer> list2
4,6,3,4,5,3
3,4,5,6,3,2
4,5,6,4,3,2
3,4,3,2,4,5
4,5,3,2,5,3
4,3,4,5,3,2
4,4,3,2,4,5
7,5,4,5,6,7
6,4,3,5,6,4

我得到以下输出：

====new list====
count = 0  count%2 = 0  state = false  lastState = false  output.size() = 1  output[i].size() = 0
count = 1  count%2 = 1  state = true  lastState = true  output.size() = 1  output[i].size() = 1
count = 1  count%2 = 1  state = true  lastState = true  output.size() = 1  output[i].size() = 2
count = 1  count%2 = 1  state = true  lastState = true  output.size() = 1  output[i].size() = 3
count = 1  count%2 = 1  state = true  lastState = true  output.size() = 1  output[i].size() = 4
count = 1  count%2 = 1  state = true  lastState = true  output.size() = 1  output[i].size() = 5
count = 1  count%2 = 1  state = true  lastState = true  output.size() = 1  output[i].size() = 6
====new list====
count = 2  count%2 = 0  state = false  lastState = false  output.size() = 2  output[i].size() = 0
====new list====
count = 2  count%2 = 0  state = false  lastState = false  output.size() = 3  output[i].size() = 0
====new list====
count = 2  count%2 = 0  state = false  lastState = false  output.size() = 4  output[i].size() = 0
count = 3  count%2 = 1  state = true  lastState = true  output.size() = 4  output[i].size() = 1
count = 3  count%2 = 1  state = true  lastState = true  output.size() = 4  output[i].size() = 2
count = 3  count%2 = 1  state = true  lastState = true  output.size() = 4  output[i].size() = 3
count = 3  count%2 = 1  state = true  lastState = true  output.size() = 4  output[i].size() = 4
count = 3  count%2 = 1  state = true  lastState = true  output.size() = 4  output[i].size() = 5
count = 3  count%2 = 1  state = true  lastState = true  output.size() = 4  output[i].size() = 6
count = 3  count%2 = 1  state = true  lastState = true  output.size() = 4  output[i].size() = 7
count = 3  count%2 = 1  state = true  lastState = true  output.size() = 4  output[i].size() = 8
count = 3  count%2 = 1  state = true  lastState = true  output.size() = 4  output[i].size() = 9

这几乎是我想要的，除了它是为每一个状态变化创建额外的列表，而不是每一个第二个状态变化，这就是我想要的。。

我已经和它混在一起很久了，我似乎不能让它做我想让它做的事情。我确定这是非常简单的事情，但我一生都无法解决它。还有其他人知道它为什么要这样做吗？任何帮助将不胜感激。谢谢！

Answer 1

经过多次试验和反复推敲，我终于找到了答案..如果有人对类似的问题感兴趣或者被它困住，这里的这段代码:

if (count % 2 == 0)
    {
        output.add(new ArrayList<int[]>());
        System.out.println("====new list====");
        i++;
    }

需要更改为：

if (count % 4 == 0)
    {
        output.add(new ArrayList<int[]>());
        System.out.println("====new list====");
        count++;
        i++;
    }

模4确保每2个状态改变就触发一次，而不是每次状态改变，计数确保计数% 4！= 0，因此创建另一个列表..

嘘！这很烦人，但很高兴解决了！