在JPA results in table中映射映射在此描述符中不存在

Question

@OneToMany
private Map<Stage, ScoreCard> scoreCards;

[EL Sersion]:2018-01-11 21:11:10.755--ServerSession(53937593)--Exception[EclipseLink-0]（Eclipse Persistence Services-2.7.0.v20170811-D680AF5):org.Eclipse.Persistence.exceptions.IntegrityException描述符

异常[EclipseLink-93]（Eclipse Persistence Services-2.7.0.v20170811-D680AF5):org.Eclipse.Persistence.exceptions.Description异常描述：表[SCORECARD]不在此描述符中。描述符:RelationalDescriptor(fi.ipsc_result_server.domain.resultData.CompetitorResultData-->[DatabaseTable(COMPETITORRESULTDATA)])

Exception[EclipseLink-41](Eclipse Persistence Services-2.7.0.V20170811-D680AF5):org.Eclipse.Persistence.exceptions.Description异常描述：必须为序号字段定义非只读映射。描述符:RelationalDescriptor(fi.ipsc_result_server.domain.resultData.CompetitorResultData-->[DatabaseTable(COMPETITORRESULTDATA)])

@Entity
public class TestClass {

    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE)
    Long id;

    @OneToMany
    @MapKeyJoinColumn(name="testKey")
    Map<TestKeyClass, TestValueClass> testMap;

[getters and setters]
}
package fi.ipsc_result_server.domain.ResultData;
@Entity
public class TestKeyClass {
    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE)
    Long id;

[getter and setter for id]
}

package fi.ipsc_result_server.domain.ResultData;

@Entity
public class TestValueClass {
    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE)
    Long id;

[getter and setter for id]
}

Answer 1

map 可以与@onetomany和@manytomany一起使用。您只需添加一个附加注释：

@OneToMany
@MapKeyJoinColumn(name="stage")
private Map<Stage, ScoreCard> scoreCards;

其中名称为：

映射键的外键列的名称。

public clas ScoreCard{

  @ManyToOne
  private Stage stage;
}