应用程序在模拟器上工作得非常好，但在我的设备上运行时，它不会登录/注册

Question

我没有太多的信息可以提供，因为我不知道问题是什么。当我在模拟器上运行它时，它工作得很好，但是当我试图在我的设备上运行它时，我无法通过登录/注册。这是我的登录代码，非常直接，注册是几乎相同的，所以我不会费心去发布它：

class LoginActivity : AppCompatActivity() {

    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        setContentView(R.layout.activity_login)

        login_button.setOnClickListener {

            performLogin()

        }

    }


    fun backToRegistration (view : View) {
        val registerIntent = Intent (this, RegisterActivity::class.java)
        startActivity(registerIntent)
    }

    private fun performLogin(){

        val logEmail = login_email.text.toString()
        val logPass = login_password.text.toString()

        Log.d("Main", "email is $logEmail")
        Log.d("Main", "pass is $logPass")

//        Patterns.EMAIL_ADDRESS.matcher(logEmail).matches()  <--- this method was used before for the if statement but I've replaced it as I kept getting the invalid email error for some reason.

        if (logEmail.contains("@") && logEmail.contains(".")) {

            if (logPass.length > 5) {

                FirebaseAuth.getInstance().signInWithEmailAndPassword(logEmail, logPass).addOnCompleteListener {
                    if (it.isSuccessful) {
                        Log.d("Login", "Successfully logged a user in using uid: ${it.result?.user?.uid}")
                        val intent = Intent(this, MainActivity::class.java)
                        intent.flags = Intent.FLAG_ACTIVITY_CLEAR_TASK.or(Intent.FLAG_ACTIVITY_NEW_TASK)
                        startActivity(intent)
                        return@addOnCompleteListener
                    }
                    //else if successful
                    Log.d("Login", "Failed to log in a user")

                }.addOnFailureListener {
                    Log.d("Main", "Failed to create user : ${it.message}")
                }
            } else {
                Toast.makeText(this, "Your password needs to be at least 6 characters long", Toast.LENGTH_LONG)
                    .show()
            }


        } else {
            Toast.makeText(this, "Please enter a valid email address", Toast.LENGTH_LONG).show()
        }

    }


}

这是我尝试登录后的logcat（级别设置为错误）：

2019-03-12 17:23:56.496 730-17078/? E/voice: voice_is_in_call:in_call 0
2019-03-12 17:23:56.496 730-17078/? E/voice: voice_is_in_call:in_call 0
2019-03-12 17:23:56.496 730-17078/? E/voice: voice_is_in_call:in_call 0
2019-03-12 17:23:56.497 730-17078/? E/msm8974_platform: platform_check_backends_match: Invalid snd_device = 
2019-03-12 17:23:56.497 730-17078/? E/soundtrigger: audio_extn_sound_trigger_update_stream_status: invalid input device 0x0, for event 3
2019-03-12 17:23:57.290 3268-12575/? E/Volley: [2631] BasicNetwork.performRequest: Unexpected response code 400 for https://www.googleapis.com/identitytoolkit/v3/relyingparty/verifyPassword?alt=proto&key=AIzaSyDVSMXQ9fymqlaJiaDogQt7i6-5j3xUbmY
2019-03-12 17:23:57.370 884-1070/? E/libc: Access denied finding property "sys.thermal.para"
2019-03-12 17:23:58.028 912-976/? E/storaged: getDiskStats failed with result NOT_SUPPORTED and size 0
2019-03-12 17:23:59.683 730-5610/? E/soundtrigger: audio_extn_sound_trigger_update_stream_status: invalid input device 0x0, for event 2
2019-03-12 17:24:02.371 884-1070/? E/libc: Access denied finding property "sys.thermal.para"
2019-03-12 17:24:07.379 884-1070/? E/libc: Access denied finding property "sys.thermal.para"
2019-03-12 17:24:12.380 884-1070/? E/libc: Access denied finding property "sys.thermal.para"

Answer 1

对于任何面临同样问题的人，根据你的情况，这里有两种可能的解决方案。

>

如果你的应用程序在app store上，并且你遇到了这个问题，请参考此处发布的答案谢谢@Swati将其提交给我。

如果您只是试图在手机上运行它进行测试，请确保您在Firebase项目中提供了SHA证书指纹。如果你不确定这意味着什么，去你的项目设置-

您需要输入两个SHA-1

要让他们进入你的Android项目，点击窗口右上角的“Gradle”选项卡（使用windows，不确定mac）。

然后导航到您的项目-

它应该在你的窗口底部运行一些行，你的日志猫通常在那里，在它们中你会发现SHA-1和SHA256