我希望有一个用C编写的程序,可以在没有openssl这样的大型库的帮助下,用AES-CBC对字符串进行编码/解码。
目标:
使用密码短语对字符串进行编码/解码:
因此,应用程序需要接受3个输入参数。。。
我对C语言不熟悉(我可以用C#编码)。
我已经找到了https://github.com/kokke/tiny-AES128-C,我需要配置,但我不确定这些功能是否足以做我想要的(见上文)
我当前的“main”代码在这里,它接受3个输入参数,然后根据第3个参数(“e”或“d”)调用函数encode/decode。
int main(int argc, char *argv[]) {
int i;
for (i = 0; i < argc; i++)
printf("i = %d, argv = %s\n", i, argv[i]);
if (argc < 4)
printf("missing args: input_text passphrase function\n");
else {
/*
... argv[1]; input_string
... argv[2]; passphrase
... argv[3]; function
*/
//encode if e
if( argv[3] == "e" ){
printf("encoded: " + encode(argv[1], argv[2]) );
} else { //decode else
printf("decoded: " + decode(argv[1], argv[2]) );
}
//printf("input: " + input);
}
return 0;
}
以下是完整的代码:
#include <stdio.h>
#include <string.h>
#include <stdint.h>
// Enable both ECB and CBC mode. Note this can be done before including aes.h or at compile-time.
// E.g. with GCC by using the -D flag: gcc -c aes.c -DCBC=0 -DECB=1
#define CBC 1
#define ECB 1
#include "aes.h"
static void phex(uint8_t* str);
static void test_encrypt_ecb(void);
static void test_decrypt_ecb(void);
static void test_encrypt_ecb_verbose(void);
static void test_encrypt_cbc(void);
static void test_decrypt_cbc(void);
int main(int argc, char *argv[]) {
int i;
for (i = 0; i < argc; i++)
printf("i = %d, argv = %s\n", i, argv[i]);
if (argc < 4)
printf("missing args: input_text passphrase function\n");
else {
/*
... argv[1]; input_string
... argv[2]; passphrase
... argv[3]; function
*/
//encode if e
if( argv[3] == "e" ){
printf("encoded: " + encode(argv[1], argv[2]) );
} else { //decode else
printf("decoded: " + decode(argv[1], argv[2]) );
}
//printf("input: " + input);
}
return 0;
}
// prints string as hex
static void phex(uint8_t* str)
{
unsigned char i;
for(i = 0; i < 16; ++i)
printf("%.2x", str[i]);
printf("\n");
}
static void test_encrypt_ecb_verbose(void)
{
// Example of more verbose verification
uint8_t i, buf[64], buf2[64];
// 128bit key
uint8_t key[16] = { (uint8_t) 0x2b, (uint8_t) 0x7e, (uint8_t) 0x15, (uint8_t) 0x16, (uint8_t) 0x28, (uint8_t) 0xae, (uint8_t) 0xd2, (uint8_t) 0xa6, (uint8_t) 0xab, (uint8_t) 0xf7, (uint8_t) 0x15, (uint8_t) 0x88, (uint8_t) 0x09, (uint8_t) 0xcf, (uint8_t) 0x4f, (uint8_t) 0x3c };
// 512bit text
uint8_t plain_text[64] = { (uint8_t) 0x6b, (uint8_t) 0xc1, (uint8_t) 0xbe, (uint8_t) 0xe2, (uint8_t) 0x2e, (uint8_t) 0x40, (uint8_t) 0x9f, (uint8_t) 0x96, (uint8_t) 0xe9, (uint8_t) 0x3d, (uint8_t) 0x7e, (uint8_t) 0x11, (uint8_t) 0x73, (uint8_t) 0x93, (uint8_t) 0x17, (uint8_t) 0x2a,
(uint8_t) 0xae, (uint8_t) 0x2d, (uint8_t) 0x8a, (uint8_t) 0x57, (uint8_t) 0x1e, (uint8_t) 0x03, (uint8_t) 0xac, (uint8_t) 0x9c, (uint8_t) 0x9e, (uint8_t) 0xb7, (uint8_t) 0x6f, (uint8_t) 0xac, (uint8_t) 0x45, (uint8_t) 0xaf, (uint8_t) 0x8e, (uint8_t) 0x51,
(uint8_t) 0x30, (uint8_t) 0xc8, (uint8_t) 0x1c, (uint8_t) 0x46, (uint8_t) 0xa3, (uint8_t) 0x5c, (uint8_t) 0xe4, (uint8_t) 0x11, (uint8_t) 0xe5, (uint8_t) 0xfb, (uint8_t) 0xc1, (uint8_t) 0x19, (uint8_t) 0x1a, (uint8_t) 0x0a, (uint8_t) 0x52, (uint8_t) 0xef,
(uint8_t) 0xf6, (uint8_t) 0x9f, (uint8_t) 0x24, (uint8_t) 0x45, (uint8_t) 0xdf, (uint8_t) 0x4f, (uint8_t) 0x9b, (uint8_t) 0x17, (uint8_t) 0xad, (uint8_t) 0x2b, (uint8_t) 0x41, (uint8_t) 0x7b, (uint8_t) 0xe6, (uint8_t) 0x6c, (uint8_t) 0x37, (uint8_t) 0x10 };
memset(buf, 0, 64);
memset(buf2, 0, 64);
// print text to encrypt, key and IV
printf("ECB encrypt verbose:\n\n");
printf("plain text:\n");
for(i = (uint8_t) 0; i < (uint8_t) 4; ++i)
{
phex(plain_text + i * (uint8_t) 16);
}
printf("\n");
printf("key:\n");
phex(key);
printf("\n");
// print the resulting cipher as 4 x 16 byte strings
printf("ciphertext:\n");
for(i = 0; i < 4; ++i)
{
AES128_ECB_encrypt(plain_text + (i*16), key, buf+(i*16));
phex(buf + (i*16));
}
printf("\n");
}
static void test_encrypt_ecb(void)
{
uint8_t key[] = {0x2b, 0x7e, 0x15, 0x16, 0x28, 0xae, 0xd2, 0xa6, 0xab, 0xf7, 0x15, 0x88, 0x09, 0xcf, 0x4f, 0x3c};
uint8_t in[] = {0x6b, 0xc1, 0xbe, 0xe2, 0x2e, 0x40, 0x9f, 0x96, 0xe9, 0x3d, 0x7e, 0x11, 0x73, 0x93, 0x17, 0x2a};
uint8_t out[] = {0x3a, 0xd7, 0x7b, 0xb4, 0x0d, 0x7a, 0x36, 0x60, 0xa8, 0x9e, 0xca, 0xf3, 0x24, 0x66, 0xef, 0x97};
uint8_t buffer[16];
AES128_ECB_encrypt(in, key, buffer);
printf("ECB decrypt: ");
if(0 == memcmp((char*) out, (char*) buffer, 16))
{
printf("SUCCESS!\n");
}
else
{
printf("FAILURE!\n");
}
}
static void test_decrypt_cbc(void)
{
// Example "simulating" a smaller buffer...
uint8_t key[] = { 0x2b, 0x7e, 0x15, 0x16, 0x28, 0xae, 0xd2, 0xa6, 0xab, 0xf7, 0x15, 0x88, 0x09, 0xcf, 0x4f, 0x3c };
uint8_t iv[] = { 0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07, 0x08, 0x09, 0x0a, 0x0b, 0x0c, 0x0d, 0x0e, 0x0f };
uint8_t in[] = { 0x76, 0x49, 0xab, 0xac, 0x81, 0x19, 0xb2, 0x46, 0xce, 0xe9, 0x8e, 0x9b, 0x12, 0xe9, 0x19, 0x7d,
0x50, 0x86, 0xcb, 0x9b, 0x50, 0x72, 0x19, 0xee, 0x95, 0xdb, 0x11, 0x3a, 0x91, 0x76, 0x78, 0xb2,
0x73, 0xbe, 0xd6, 0xb8, 0xe3, 0xc1, 0x74, 0x3b, 0x71, 0x16, 0xe6, 0x9e, 0x22, 0x22, 0x95, 0x16,
0x3f, 0xf1, 0xca, 0xa1, 0x68, 0x1f, 0xac, 0x09, 0x12, 0x0e, 0xca, 0x30, 0x75, 0x86, 0xe1, 0xa7 };
uint8_t out[] = { 0x6b, 0xc1, 0xbe, 0xe2, 0x2e, 0x40, 0x9f, 0x96, 0xe9, 0x3d, 0x7e, 0x11, 0x73, 0x93, 0x17, 0x2a,
0xae, 0x2d, 0x8a, 0x57, 0x1e, 0x03, 0xac, 0x9c, 0x9e, 0xb7, 0x6f, 0xac, 0x45, 0xaf, 0x8e, 0x51,
0x30, 0xc8, 0x1c, 0x46, 0xa3, 0x5c, 0xe4, 0x11, 0xe5, 0xfb, 0xc1, 0x19, 0x1a, 0x0a, 0x52, 0xef,
0xf6, 0x9f, 0x24, 0x45, 0xdf, 0x4f, 0x9b, 0x17, 0xad, 0x2b, 0x41, 0x7b, 0xe6, 0x6c, 0x37, 0x10 };
uint8_t buffer[64];
AES128_CBC_decrypt_buffer(buffer+0, in+0, 16, key, iv);
AES128_CBC_decrypt_buffer(buffer+16, in+16, 16, 0, 0);
AES128_CBC_decrypt_buffer(buffer+32, in+32, 16, 0, 0);
AES128_CBC_decrypt_buffer(buffer+48, in+48, 16, 0, 0);
printf("CBC decrypt: ");
if(0 == memcmp((char*) out, (char*) buffer, 64))
{
printf("SUCCESS!\n");
}
else
{
printf("FAILURE!\n");
}
}
static void test_encrypt_cbc(void)
{
uint8_t key[] = { 0x2b, 0x7e, 0x15, 0x16, 0x28, 0xae, 0xd2, 0xa6, 0xab, 0xf7, 0x15, 0x88, 0x09, 0xcf, 0x4f, 0x3c };
uint8_t iv[] = { 0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07, 0x08, 0x09, 0x0a, 0x0b, 0x0c, 0x0d, 0x0e, 0x0f };
uint8_t in[] = { 0x6b, 0xc1, 0xbe, 0xe2, 0x2e, 0x40, 0x9f, 0x96, 0xe9, 0x3d, 0x7e, 0x11, 0x73, 0x93, 0x17, 0x2a,
0xae, 0x2d, 0x8a, 0x57, 0x1e, 0x03, 0xac, 0x9c, 0x9e, 0xb7, 0x6f, 0xac, 0x45, 0xaf, 0x8e, 0x51,
0x30, 0xc8, 0x1c, 0x46, 0xa3, 0x5c, 0xe4, 0x11, 0xe5, 0xfb, 0xc1, 0x19, 0x1a, 0x0a, 0x52, 0xef,
0xf6, 0x9f, 0x24, 0x45, 0xdf, 0x4f, 0x9b, 0x17, 0xad, 0x2b, 0x41, 0x7b, 0xe6, 0x6c, 0x37, 0x10 };
uint8_t out[] = { 0x76, 0x49, 0xab, 0xac, 0x81, 0x19, 0xb2, 0x46, 0xce, 0xe9, 0x8e, 0x9b, 0x12, 0xe9, 0x19, 0x7d,
0x50, 0x86, 0xcb, 0x9b, 0x50, 0x72, 0x19, 0xee, 0x95, 0xdb, 0x11, 0x3a, 0x91, 0x76, 0x78, 0xb2,
0x73, 0xbe, 0xd6, 0xb8, 0xe3, 0xc1, 0x74, 0x3b, 0x71, 0x16, 0xe6, 0x9e, 0x22, 0x22, 0x95, 0x16,
0x3f, 0xf1, 0xca, 0xa1, 0x68, 0x1f, 0xac, 0x09, 0x12, 0x0e, 0xca, 0x30, 0x75, 0x86, 0xe1, 0xa7 };
uint8_t buffer[64];
AES128_CBC_encrypt_buffer(buffer, in, 64, key, iv);
printf("CBC encrypt: ");
if(0 == memcmp((char*) out, (char*) buffer, 64))
{
printf("SUCCESS!\n");
}
else
{
printf("FAILURE!\n");
}
}
static void test_decrypt_ecb(void)
{
uint8_t key[] = {0x2b, 0x7e, 0x15, 0x16, 0x28, 0xae, 0xd2, 0xa6, 0xab, 0xf7, 0x15, 0x88, 0x09, 0xcf, 0x4f, 0x3c};
uint8_t in[] = {0x3a, 0xd7, 0x7b, 0xb4, 0x0d, 0x7a, 0x36, 0x60, 0xa8, 0x9e, 0xca, 0xf3, 0x24, 0x66, 0xef, 0x97};
uint8_t out[] = {0x6b, 0xc1, 0xbe, 0xe2, 0x2e, 0x40, 0x9f, 0x96, 0xe9, 0x3d, 0x7e, 0x11, 0x73, 0x93, 0x17, 0x2a};
uint8_t buffer[16];
AES128_ECB_decrypt(in, key, buffer);
printf("ECB decrypt: ");
if(0 == memcmp((char*) out, (char*) buffer, 16))
{
printf("SUCCESS!\n");
}
else
{
printf("FAILURE!\n");
}
}
正如你在问题中所说:
目标:
>
用密码编码/解码字符串:
因此,应用程序需要接受3个输入参数。。。
输入字符串(待编码)(明文)
或已编码字符串(待解码)(密文)
密码短语,用于使用encode或decode指示符对字符串进行编码/解码
这里,这是AES源代码,文件太长,我在这里没有,但总共有4个文件:
http://www.efgh.com/software/rijndael.htm
http://www.efgh.com/software/rijndael.txt
这些是:
>
解密。C
瑞恩代尔。H
jjndael. c
http://www.efgh.com/software/rijndael.txt
将有以下4行分隔文件:
(在这里,创建4个单独的文件,其内容为=separation=)
因此,为了展示一个简短的示例,RIJNDAEL. H文件,其内容如下:
//=============================== RIJNDAEL.H ===============================
#ifndef H__RIJNDAEL
#define H__RIJNDAEL
int rijndaelSetupEncrypt(unsigned long *rk, const unsigned char *key,
int keybits);
int rijndaelSetupDecrypt(unsigned long *rk, const unsigned char *key,
int keybits);
void rijndaelEncrypt(const unsigned long *rk, int nrounds,
const unsigned char plaintext[16], unsigned char ciphertext[16]);
void rijndaelDecrypt(const unsigned long *rk, int nrounds,
const unsigned char ciphertext[16], unsigned char plaintext[16]);
#define KEYLENGTH(keybits) ((keybits)/8)
#define RKLENGTH(keybits) ((keybits)/8+28)
#define NROUNDS(keybits) ((keybits)/32+6)
#endif
=============================== DECRYPT. C ===============================
=============================== ENCRYPT. C ===============================
===========================================================================================================================RIJNDAEL。C===============================
=============================== RIJNDAEL. H ===============================
对每个文件执行此操作。c、 解密。里杰代尔。c最后是rijndael。H
测试结果:
$ gcc -o AES_ENCRYPT RIJNDAEL.C ENCRYPT.C
$ gcc -o AES_DECRYPT RIJNDAEL.C DECRYPT.C
加密信息“您要加密的秘密信息在这里。(明文)
到输出文件“EncodedOutputFile”
$ ./AES_ENCRYPT MySecurePassword123 EncodedOutputFile
Your secret message to be encrypted goes here. (The plaintext)
CTRL + D to stop.
要解密密文(加密文件EncodedOutputFile):
$ ./AES_DECRYPT MySecurePassword123 EncodedOutputFile
这是输出
Your secret message to be encrypted goes here. (The plaintext)
CTRL + D to stop.
我只想用这3种模式测试openSSL中的AES:128192和256密钥长度,但我解密的文本与我的输入不同,我不知道为什么。此外,当我传递一个巨大的输入长度(比如1024字节)时,我的程序显示。。。我的意见总是一样的,但这并不重要,至少现在是这样。代码如下: 编辑: 当我将输出大小更改为而不是时,我得到了结果: 那么,是否有可能存在Outpus大小和IV大小的问题?它们应该有什么尺寸(AES-CB
我用java编写了这段代码,以便解密密文。我有钥匙。对我来说,一切都是正确的,但我有我要解释的问题。 这是我的代码: 我收到以下错误: 出了什么问题?我知道这个问题在某种程度上与衬垫有关,但我不知道确切的解决方案。我只有一个密文IV和密钥。
问题内容: 我在解密以前在PHP应用程序中加密过的pgcrypto中的数据时遇到问题。 我尝试了3种加密类型: 1)mcrypt-RIJNDAEL 128 CBC 2)mcrypt-RIJNDAEL 256 CBC 3)openssl_encrypt-aes-256-cbc 一切都在PHP中很好地解密,但是在pgcrypto中,我只能使用相同的密钥和iv进行解密1)mcrypt-RIJNDAEL
我只需要通过代码加密AES CBC 128位模式的字符串。我使用openssl库完成了这项工作,但无法获得正确的输出。 到目前为止,我已经完成了。 我的十六进制输出是:B0 15 751B50 80 D4 FF 81 68 146BB71B95 99 37 38 但正确的输出是:< code > 73 5C 04 F9 57 18 43 7C EE 68 27 59 2B 41 A8 DA (通过
我在pgcrypto中解密以前在PHP应用程序中加密的数据时遇到问题。 我尝试了3种类型的加密: 1)mcrypt-rijndael 128 cbc 2)mcrypt-rijndael 256 cbc 3)openssl_encrypt-aes-256-cbc 在PHP中,所有的东西都可以加密解密,但在pgcrypto中,我可以使用相同的密钥和iv解密,仅1)mcrypt-rijndael 128