如何全局设置Jackson在Spring中忽略未知属性？

Question

@JsonIgnoreProperties(ignoreUnknown = true) 

@JsonIgnore

// jackson 1.9 and before
objectMapper.configure(DeserializationConfig.Feature.FAIL_ON_UNKNOWN_PROPERTIES, false);
// or jackson 2.0
objectMapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);

Answer 1

对于Jackson1.9x或更低版本，可以使用对象映射器提供程序忽略未知属性

@Provider
@Component
public class JerseyObjectMapperProvider implements ContextResolver<ObjectMapper> {

    @Override
    public ObjectMapper getContext(Class<?> type) {

        ObjectMapper result = new ObjectMapper();
        result.configure(DeserializationConfig.Feature.FAIL_ON_UNKNOWN_PROPERTIES, false);
        return result;
    }
}

对于Jackson2.x及以上版本，您可以使用对象映射器提供程序忽略未知属性

@Provider
@Component
public class JerseyObjectMapperProvider implements ContextResolver<ObjectMapper> {

    @Override
    public ObjectMapper getContext(Class<?> type) {

        ObjectMapper result = new ObjectMapper();
        result.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
        return result;
    }
}

Spring不会自动发现泽西类。必须手动登记。

public class JerseyConfig extends ResourceConfig {
    public JerseyConfig() {
        register(JerseyObjectMapperProvider.class);
    }
}