Django-创建一个包含多个文件的邮政编码，并使其可下载

Question

（如果我错过了任何重复的内容，请随时向我指出）

我查看了以下代码段：http :
//djangosnippets.org/snippets/365/

和这个答案：

但是我不知道如何调整它们以适应我的需要：我想压缩多个文件，并希望通过链接（或通过视图动态生成）下载存档。我是Python和Django的新手，所以我不知道该怎么做。

预先感谢！

Answer 1

我已经在Willy链接到的重复问题上发布了此问题，但是由于无法将包含悬赏的问题作为重复问题解决，因此也可以在此处将其复制：

import os
import zipfile
import StringIO

from django.http import HttpResponse


def getfiles(request):
    # Files (local path) to put in the .zip
    # FIXME: Change this (get paths from DB etc)
    filenames = ["/tmp/file1.txt", "/tmp/file2.txt"]

    # Folder name in ZIP archive which contains the above files
    # E.g [thearchive.zip]/somefiles/file2.txt
    # FIXME: Set this to something better
    zip_subdir = "somefiles"
    zip_filename = "%s.zip" % zip_subdir

    # Open StringIO to grab in-memory ZIP contents
    s = StringIO.StringIO()

    # The zip compressor
    zf = zipfile.ZipFile(s, "w")

    for fpath in filenames:
        # Calculate path for file in zip
        fdir, fname = os.path.split(fpath)
        zip_path = os.path.join(zip_subdir, fname)

        # Add file, at correct path
        zf.write(fpath, zip_path)

    # Must close zip for all contents to be written
    zf.close()

    # Grab ZIP file from in-memory, make response with correct MIME-type
    resp = HttpResponse(s.getvalue(), mimetype = "application/x-zip-compressed")
    # ..and correct content-disposition
    resp['Content-Disposition'] = 'attachment; filename=%s' % zip_filename

    return resp