ORACLE（11.2.0.1.0）-具有日期表达式的递归CTE

Question

以下问题的正确答案：

如果我没有记错的话，那是在11.2.0.3或更高版本中修复的错误。（无论如何不再支持11.2.0.1.11.2.0.4是唯一仍受支持的11.2版本）-@a_horse_with_no_name
错误号为11840579，已在11.2.0.3和12.1.0.1中进行了修复-@a_horse_with_no_name问题

I have a table

CREATE TABLE test(
  from_date date,
  to_date date
);

INSERT INTO test(from_date,to_date)
--VALUES('20171101','20171115');
VALUES(TO_DATE('20171101','YYYYMMDD'),TO_DATE('20171115','YYYYMMDD'));

The following query in Oracle return only one row (expected 15 rows)

WITH dateCTE(from_date,to_date,d,i) AS(
  SELECT from_date,to_date,from_date AS d,1 AS i
  FROM test

  UNION ALL

  SELECT from_date,to_date,d+INTERVAL '1' DAY,i+1
  FROM dateCTE
  WHERE d<to_date
)
SELECT d,i
FROM dateCTE

SQL Fiddle - http://sqlfiddle.com/#!4/36907/8

For test I changed the condition to i<10

WITH dateCTE(from_date,to_date,d,i) AS(
  SELECT from_date,to_date,from_date AS d,1 AS i
  FROM test

  UNION ALL

  SELECT from_date,to_date,d+INTERVAL '1' DAY,i+1
  FROM dateCTE
  --WHERE d<to_date
  WHERE i<10 -- exit condition
)
SELECT d,i
FROM dateCTE

And get the next result

| D          | I  |
|------------|----|
| 2017-11-01 |  1 |
| 2017-10-31 |  2 |
| 2017-10-30 |  3 |
| 2017-10-29 |  4 |
| 2017-10-28 |  5 |
| 2017-10-27 |  6 |
| 2017-10-26 |  7 |
| 2017-10-25 |  8 |
| 2017-10-24 |  9 |
| 2017-10-23 | 10 |

Why do this recursive query returned bad result in Oracle?

SQL Fiddle - http://sqlfiddle.com/#!4/36907/5

为了进行测试，我将条件更改为 i<10

WITH dateCTE(from_date,to_date,d,i) AS(
  SELECT from_date,to_date,from_date AS d,1 AS i
  FROM test

  UNION ALL

  SELECT from_date,to_date,DATEADD(DAY,1,d),i+1
  FROM dateCTE
  WHERE d<to_date
)
SELECT d,i
FROM dateCTE

The right result

d           i
2017-11-01  1
2017-11-02  2
2017-11-03  3
2017-11-04  4
2017-11-05  5
2017-11-06  6
2017-11-07  7
2017-11-08  8
2017-11-09  9
2017-11-10  10
2017-11-11  11
2017-11-12  12
2017-11-13  13
2017-11-14  14
2017-11-15  15

Answer 1

如果您希望有一个连续的起始日期到最新日期，请使用以下选择：

SELECT  DATE '2017-11-01' + LEVEL - 1 AS D, LEVEL AS I
FROM DUAL
CONNECT BY LEVEL <= DATE '2017-11-15' - DATE '2017-11-01' + 1;