在React JS中按日期对数组进行排序

Question

我有一个对象数组，如下所示：

let cars = [
    {"id":20,"mileage":41300,"make":"Golf", initialRegistration:"09/02/2010"}, 
    {"id":21,"mileage":51300,"make":"Passat", initialRegistration:"06/04/2012"},
    {"id":22,"mileage":61300,"make":"Audi", initialRegistration:"02/01/2018"},
    {"id":23,"mileage":20300,"make":"Touran", initialRegistration:"17/09/2013"},
    {"id":24,"mileage":10300,"make":"Polo", initialRegistration:"26/07/2014"}
];

我想按排序initialRegistration。

我尝试这样做如下：

let sortedCars = cars.sort((a, b) => Date.parse(a.initialRegistration) - Date.parse(b.initialRegistration));

let sortedCars1 = cars.sort((a, b) => new Date(a.initialRegistration) - new Date(b.initialRegistration));

let sortedCars2 = cars.sort((a, b) => new Date(a.initialRegistration).getTime() - new Date(b.initialRegistration).getTime());

但是这些尝试都没有成功。我得到的结果是：

Golf - 09/02/2010
Passat - 06/04/2012
Audi - 02/01/2018
Touran - 17/09/2013
Polo - 26/07/2014

这是小提琴。

Answer 1

使用Date构造函数并执行类似的操作。

let sortedCars1 = cars.sort((a, b) => new Date(...a.initialRegistration.split('/').reverse()) - new Date(...b.initialRegistration.split('/').reverse()));



let cars = [{

  "id": 20,

  "mileage": 41300,

  "make": "Golf",

  initialRegistration: "09/02/2010"

}, {

  "id": 21,

  "mileage": 51300,

  "make": "Passat",

  initialRegistration: "06/04/2012"

}, {

  "id": 22,

  "mileage": 61300,

  "make": "Audi",

  initialRegistration: "02/01/2018"

}, {

  "id": 23,

  "mileage": 20300,

  "make": "Touran",

  initialRegistration: "17/09/2013"

}, {

  "id": 24,

  "mileage": 10300,

  "make": "Polo",

  initialRegistration: "26/07/2014"

}];



let sortedCars1 = cars.sort((a, b) => new Date(...a.initialRegistration.split('/').reverse()) - new Date(...b.initialRegistration.split('/').reverse()));



console.log(sortedCars1);

或通过String#localeCompare将日期字符串反转后使用字符串比较。

let sortedCars1 = cars.sort((a, b) =>
  a.initialRegistration.split('/').reverse().join().localeCompare(b.initialRegistration.split('/').reverse().join()));



let cars = [{

  "id": 20,

  "mileage": 41300,

  "make": "Golf",

  initialRegistration: "09/02/2010"

}, {

  "id": 21,

  "mileage": 51300,

  "make": "Passat",

  initialRegistration: "06/04/2012"

}, {

  "id": 22,

  "mileage": 61300,

  "make": "Audi",

  initialRegistration: "02/01/2018"

}, {

  "id": 23,

  "mileage": 20300,

  "make": "Touran",

  initialRegistration: "17/09/2013"

}, {

  "id": 24,

  "mileage": 10300,

  "make": "Polo",

  initialRegistration: "26/07/2014"

}];



let sortedCars1 = cars.sort((a, b) =>

  a.initialRegistration.split('/').reverse().join().localeCompare(b.initialRegistration.split('/').reverse().join()));



console.log(sortedCars1);