确保带有子流程的Python脚本在SIGINT上消失

Question

我有一个要包装的命令，script并使用从Python脚本生成subprocess.Popen。我正在尝试确保它在用户发出时消失SIGINT。

我可以弄清楚该过程是否至少以两种方式中断了：

A.如果包装的命令的退出状态为非零，则死掉（无效，因为script似乎总是返回0）

B.SIGINT在父Python脚本中做一些特别的事情，而不是简单地中断子进程。我尝试了以下方法：

import sys
import signal
import subprocess

def interrupt_handler(signum, frame):
    print "While there is a 'script' subprocess alive, this handler won't executes"
    sys.exit(1)
signal.signal(signal.SIGINT, interrupt_handler)

for n in range( 10 ):
    print "Going to sleep for 2 second...Ctrl-C to exit the sleep cycles"

    # exit 1 if we make it to the end of our sleep
    cmd = [ 'script', '-q', '-c', "sleep 2 && (exit 1)", '/dev/null']
    p = subprocess.Popen(cmd, stdout=subprocess.PIPE, stderr=subprocess.PIPE)

    while True:
        if p.poll() != None :
            break
        else :
            pass

    # Exiting on non-zero exit status would suffice
    print "Exit status (script always exits zero, despite what happened to the wrapped command):", p.returncode

我想按Ctrl-C退出python脚本。相反，发生的事情是子进程死亡，脚本继续。

Answer 1

这个技巧可以使用，但是很难看…

将命令更改为此：

success_flag = '/tmp/success.flag'
cmd = [ 'script', '-q', '-c', "sleep 2 && touch " + success_flag, '/dev/null']

并把

if os.path.isfile( success_flag ) :
    os.remove( success_flag )
else :
    return

在for循环的末尾