在字符串中查找重复的字符并使用Java计算出现的次数

Question

如何找到字符串中字符出现的次数？

例如：敏捷的褐狐狸跳过了那只懒狗 。

下面是一些示例输出，

'a' = 1
'o' = 4
'space' = 8
'.' = 1

Answer 1

import java.io.*;
public class CountChar 
{

    public static void main(String[] args) throws IOException
    {
      String ch;
      BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
      System.out.print("Enter the Statement:");
      ch=br.readLine();
      int count=0,len=0;
        do
        {  
          try
          {
          char name[]=ch.toCharArray();
              len=name.length;
              count=0;
              for(int j=0;j<len;j++)
               {
                  if((name[0]==name[j])&&((name[0]>=65&&name[0]<=91)||(name[0]>=97&&name[0]<=123))) 
                      count++;
               }
              if(count!=0)
                System.out.println(name[0]+" "+count+" Times");
              ch=ch.replace(""+name[0],"");          
          }
          catch(Exception ex){}
        }
        while(len!=1);
   }

}

输出量

Enter the Statement:asdf23123sfsdf

a 1 Times

s 3 Times

d 2 Times

f 3 Times