如何从HttpClient切换到HttpUrlConnection？

Question

我正在创建一个Android应用程序，并通过HttpClient将数据从Android应用程序发送到servlet。我使用HttpPost方法。

我在Android开发人员网站上了解到，Apache HttpClient库在Android Froyo
2.2中存在一些错误，毕竟使用HttpUrlConnection而不是HttpPost是一个好习惯。所以我想将我的HttpPost代码转换为HttpUrlConnectio，但不知道如何。

我在这里发布我的Android代码以及servlet代码

Android代码

private String postData(String valueIWantToSend[]) 
    {
        // Create a new HttpClient and Post Header
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(url);
        try 
        {
            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
            nameValuePairs.add(new BasicNameValuePair("param1",valueIWantToSend[0]));
            nameValuePairs.add(new BasicNameValuePair("param2", valueIWantToSend[1]));
            nameValuePairs.add(new BasicNameValuePair("param3", valueIWantToSend[2]));
            nameValuePairs.add(new BasicNameValuePair("param4", valueIWantToSend[3]));
            nameValuePairs.add(new BasicNameValuePair("param5", valueIWantToSend[4]));
            nameValuePairs.add(new BasicNameValuePair("param6", valueIWantToSend[5]));
            nameValuePairs.add(new BasicNameValuePair("param7", valueIWantToSend[6]));
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            /* execute */
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity rp = response.getEntity();

            //origresponseText=readContent(response);
        }
        catch (ClientProtocolException e) 
        {
            // TODO Auto-generated catch block
        } 
        catch (IOException e) 
        {
            // TODO Auto-generated catch block
        }
        return null;
    }

这是我的servlet代码

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    // TODO Auto-generated method stub
    response.setContentType("text/html");
    ObjectOutputStream out = new ObjectOutputStream(response.getOutputStream());
    Enumeration paramNames = request.getParameterNames();
    String params[] = new String[7];
    int i=0;

    while(paramNames.hasMoreElements())
    {
        String paramName = (String) paramNames.nextElement();
        System.out.println(paramName);


        String[] paramValues = request.getParameterValues(paramName);
        params[i] = paramValues[0];

        System.out.println(params[i]);

        i++;
    }

}

Answer 1

您绝对应该使用HttpUrlConnection：

对于Gingerbread和更好的姜饼来说，HttpURLConnection是最佳选择…新应用程序应使用HttpURLConnection …

- 谷歌（大约2011）。

但是，没有简单的方法可以“切换”。API完全不同。您将不得不重写您的网络代码。文档中提供了有关如何提交GET和POST请求以及SDK示例应用程序的完美示例。