无法动态设置setVisibility（）参数

Question

我试图按如下所示设置按钮的可见性：

public Bundle setActivityState(Bundle bundle){
    startBtn = (Button) findViewById(R.id.startSensorsBtn);

    startBtn.setVisibility(
            getVisibilityState(bundle, PersistanceConstants.START_BTN_STATE)
    );

    return bundle;
}

public int getVisibilityState(Bundle bundle, String keyName){
    if (bundle.getInt(keyName) == View.VISIBLE){
        return View.VISIBLE;
    } else if (bundle.getInt(keyName) == View.INVISIBLE){
        return View.INVISIBLE;
    } else if (bundle.getInt(keyName) == View.GONE){
        return View.GONE;
    }

    return 0;
}

但是我得到了错误：

Must be one of: View.VISIBLE, View.INVISIBLE, View.GONE less... (Ctrl+F1) 
Reports two types of problems:
- Supplying the wrong type of resource identifier. For example, when calling Resources.getString(int id), you should be passing R.string.something, not R.drawable.something.
- Passing the wrong constant to a method which expects one of a specific set of constants. For example, when calling View#setLayoutDirection, the parameter must be android.view.View.LAYOUT_DIRECTION_LTR or android.view.View.LAYOUT_DIRECTION_RTL.

在通话时

getVisibilityState(bundle, PersistanceConstants.START_BTN_STATE)

我不知道该如何解决。我知道这是期望给定的一组值，但我所知道的只是将其传递int给它。在这里可以做什么？

Answer 1

当您知道自己在做什么时，可以使用

//noinspection ResourceType

例如，

//noinspection ResourceType
startBtn.setVisibility(bundle.getInt(PersistanceConstants.START_BTN_STATE));