如何制作一个按钮，单击该按钮即可打开％appdata％目录？

Question

我已经创建了一个按钮，但是现在我不知道如何像%appdata%单击该按钮一样使它打开特定的目录。

这是代码->

//---- button4 ----
        button4.setText("Texture Packs");
        button4.addActionListener(new ActionListener() {
            public void actionPerformed(ActionEvent e)
            {
                JFileChooser fileChooser=new JFileChooser("%appdata%");
                int status = fileChooser.showOpenDialog(this);
                fileChooser.setMultiSelectionEnabled(false);

                if(status == JFileChooser.APPROVE_OPTION) {
                    File file = fileChooser.getSelectedFile();
                    // do something on the selected file.
                }


            }

我想做这样的事情->

private void button4MouseClicked(MouseEvent e) throws IOException {

           open folder %appdata% 
           // Open the folder in the file explorer not in Java.
           // When I click on the button, the folder is viewed with the file explorer on the screen
        }

Answer 1

import java.awt.Desktop;
import java.io.File;

public class OpenAppData {

    public static void main(String[] args) throws Exception {
        // Horribly platform specific.
        String appData = System.getenv("APPDATA");
        File appDataDir = new File(appData);
        // Get a sub-directory named 'texture'
        File textureDir = new File(appDataDir, "texture");
        Desktop.getDesktop().open(textureDir);
    }
}