ParseException Java

Question

我正在编写一个约会程序，该程序允许用户输入约会日期，描述和约会类型。一切正常，直到他们选择“打印范围”以打印日期范围，当他们选择执行此操作时，它告诉他们输入开始日期和结束日期，然后程序从这些日期之间提取所有约会并将它们显示在输出框中。

这是我在打印范围时遇到的错误：

AppointmentNew.java:68: unreported exception java.text.ParseException; must be caught or declared to be thrown
        Date lowDate = sdf.parse(stdin.nextLine());
                                ^
AppointmentNew.java:70: unreported exception java.text.ParseException; must be caught or declared to be thrown
        Date highDate = sdf.parse(stdin.nextLine());  
                                 ^
AppointmentNew.java:77: unreported exception java.text.ParseException; must be caught or declared to be thrown
           Date newCurrentDate = sdf.parse(currentDate);

我想我应该做一个try / catch块，但是我不确定该怎么做，并且想知道是否有人可以为我提供解决这些错误的答案或示例。

这是我认为解析错误发生的一些代码：

import java.util.*;
import java.text.SimpleDateFormat;
import java.util.Date;

public class AppointmentNew 
{
public static void main (String[] args) throws Exception
{

if (choiceNum == 2)
     {
        System.out.print("\n\n\tEnter START Date in mm/dd/yyyy format: ");
        SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");
        Date lowDate = sdf.parse(stdin.nextLine());
        System.out.print("\n\n\tEnter END Date in mm/dd/yyyy format: ");
       Date highDate = sdf.parse(stdin.nextLine());

        for(int i = 0; i < list.size(); i++)
        {
           int dateSpot = list.get(i).indexOf(" ");
           String currentDate = list.get(i);
           currentDate.substring(0, dateSpot);
           Date newCurrentDate = sdf.parse(currentDate);

           if (newCurrentDate.compareTo(lowDate) >= 0 && newCurrentDate.compareTo(highDate) <= 0)
           {
              System.out.println("\n\t" + list.get(i));

           }
        }
     }

Answer 1

解析异常是已检查的异常，因此您必须进行处理。通过掷球或尝试挡块。

public static void main (String[] args)

应该

public static void main (String[] args) throws ParseException

或者在try catch块中

try {
    //All your parse Operations
} catch (ParseException e) {
   //Handle exception here, most of the time you will just log it.
   e.printStackTrace();
  }