Spring WebSocket发送给特定的人

Question

我为spring-web应用程序添加了基于自定义令牌的身份验证，并将其扩展到spring websocket，如下所示

public class WebSocketConfig extends AbstractWebSocketMessageBrokerConfigurer {

    @Override
    public void configureMessageBroker(MessageBrokerRegistry config) {
        config.enableSimpleBroker("/topic", "/queue");
        config.setApplicationDestinationPrefixes("/app");
        config.setUserDestinationPrefix("/user");
    }

    @Override
    public void registerStompEndpoints(StompEndpointRegistry registry) {
        registry.addEndpoint("/gs-guide-websocket").setAllowedOrigins("*").withSockJS();
    }

    @Override
      public void configureClientInboundChannel(ChannelRegistration registration) {
        registration.setInterceptors(new ChannelInterceptorAdapter() {

            @Override
            public Message<?> preSend(Message<?> message, MessageChannel channel) {

                StompHeaderAccessor accessor =
                    MessageHeaderAccessor.getAccessor(message, StompHeaderAccessor.class);

                if (StompCommand.CONNECT.equals(accessor.getCommand())) {
                    String jwtToken = accessor.getFirstNativeHeader("Auth-Token");
                        if (!StringUtils.isEmpty(jwtToken)) {
                            Authentication auth = tokenService.retrieveUserAuthToken(jwtToken);
                            SecurityContextHolder.getContext().setAuthentication(auth);
                            accessor.setUser(auth);
                            //for Auth-Token '12345token' the user name is 'user1' as auth.getName() returns 'user1'
                        }
                }

                return message;
            }
        });
      }
}

连接到套接字的客户端代码是

var socket = new SockJS('http://localhost:8080/gs-guide-websocket');
    stompClient = Stomp.over(socket);
    stompClient.connect({'Auth-Token': '12345token'}, function (frame) {
        stompClient.subscribe('/user/queue/greetings', function (greeting) {
            alert(greeting.body);
        });
    });

从我的控制器发送消息为

messagingTemplate.convertAndSendToUser("user1", "/queue/greetings", "Hi User1");

对于auth令牌12345token，用户名是user1。但是，当我向发送消息时user1，它在客户端未收到。我有什么想念的吗？

Answer 1

在您的Websocket控制器中，您应该执行以下操作：

@Controller
public class GreetingController {

    @Autowired
    private SimpMessagingTemplate messagingTemplate;

    @MessageMapping("/hello")
    public void greeting(Principal principal, HelloMessage message) throws  Exception {
        Greeting greeting = new Greeting();
        greeting.setContent("Hello!");
        messagingTemplate.convertAndSendToUser(message.getToUser(), "/queue/reply", greeting);
    }
}

在客户端，您的用户应订阅主题/ user / queue / reply。

您还必须添加一些目标前缀：

@Configuration
@EnableWebSocketMessageBroker
public class WebSocketConfig extends AbstractWebSocketMessageBrokerConfigurer {

    @Override
    public void configureMessageBroker(MessageBrokerRegistry config) {
        config.enableSimpleBroker("/topic", "/queue" ,"/user");
        config.setApplicationDestinationPrefixes("/app");
        config.setUserDestinationPrefix("/user");
    }
/*...*/
}

当服务器在/ app / hello队列上收到消息时，它应该向dto中的用户发送消息。用户必须等于用户的主体。

我认为您代码中的唯一问题是您的“ /用户”不在目标前缀中。您的问候语消息被阻止，因为您将其发送到以/ user开头的队列中，并且未注册此前缀。

您可以在git repo上查看源代码：https : //github.com/simvetanylen/test-spring-
websocket

希望它能起作用！