在.txt文件中找到所有字符串“ the”

Question

这是我的代码：

// Import io so we can use file objects
import java.io.*;

public class SearchThe {
    public static void main(String args[]) {
        try {
            String stringSearch = "the";
            // Open the file c:\test.txt as a buffered reader
            BufferedReader bf = new BufferedReader(new FileReader("test.txt"));

            // Start a line count and declare a string to hold our current line.
            int linecount = 0;
                String line;

            // Let the user know what we are searching for
            System.out.println("Searching for " + stringSearch + " in file...");

            // Loop through each line, stashing the line into our line variable.
            while (( line = bf.readLine()) != null){
                // Increment the count and find the index of the word
                linecount++;
                int indexfound = line.indexOf(stringSearch);

                // If greater than -1, means we found the word
                if (indexfound > -1) {
                    System.out.println("Word was found at position " + indexfound + " on line " + linecount);
                }
            }

            // Close the file after done searching
            bf.close();
        }
        catch (IOException e) {
            System.out.println("IO Error Occurred: " + e.toString());
        }
    }
}

我想在test.txt文件中找到一些单词 “ the” 。问题是当我找到第一个 “ the”时 ，我的程序停止寻找更多东西。

当诸如 “ then” 之类的单词被我的程序理解为 “ the” 一词时。

Answer 1

不区分大小写地使用Regexes，并使用单词边界查找“ the”的所有实例和变体。

indexOf("the")无法区分 “ the” 和 “ then”， 因为它们均以“ the”开头。同样，“ the”位于 “
anathema”
的中间。

为避免这种情况，请使用正则表达式并搜索“ the”，并\b在其两边带有单词边界（）。使用单词边界，而不是在“”上分割，或者仅使用indexOf(" the ")找不到 “ the”的 （两边的空格） 。 以及标点符号旁边的其他实例。您也可以不区分大小写地搜索 “ The” 。

Pattern p = Pattern.compile("\\bthe\\b", Pattern.CASE_INSENSITIVE);

while ( (line = bf.readLine()) != null) {
    linecount++;

    Matcher m = p.matcher(line);

    // indicate all matches on the line
    while (m.find()) {
        System.out.println("Word was found at position " + 
                       m.start() + " on line " + linecount);
    }
}