在Android中使用电话号码获取联系人姓名

Question

我正在尝试根据给定的联系人电话号码检索联系人姓名。我做了一个可以在所有API版本中使用的函数，因为我无法使其在1.6版中运行，而且我也看不到问题所在，也许有人可以发现它？

请注意，我已经为字符串替换了API常量，因此没有过时的警告问题。

public String getContactName(final String phoneNumber) 
{  
    Uri uri;
    String[] projection;

    if (Build.VERSION.SDK_INT >= 5)
    {
        uri = Uri.parse("content://com.android.contacts/phone_lookup");
        projection = new String[] { "display_name" };
    }
    else
    { 
        uri = Uri.parse("content://contacts/phones/filter");
        projection = new String[] { "name" }; 
    }

    uri = Uri.withAppendedPath(uri, Uri.encode(phoneNumber)); 
    Cursor cursor = this.getContentResolver().query(uri, projection, null, null, null);

    String contactName = "";

    if (cursor.moveToFirst()) 
    { 
        contactName = cursor.getString(0);
    }

    cursor.close();
    cursor = null;

    return contactName; 
}

Answer 1

使用反射而不是比较sdk版本。

public String getContactName(final String phoneNumber) 
{  
    Uri uri;
    String[] projection;
    mBaseUri = Contacts.Phones.CONTENT_FILTER_URL;
    projection = new String[] { android.provider.Contacts.People.NAME }; 
    try {
        Class<?> c =Class.forName("android.provider.ContactsContract$PhoneLookup");
        mBaseUri = (Uri) c.getField("CONTENT_FILTER_URI").get(mBaseUri);
        projection = new String[] { "display_name" };
    } 
    catch (Exception e) {
    }


    uri = Uri.withAppendedPath(mBaseUri, Uri.encode(phoneNumber)); 
    Cursor cursor = this.getContentResolver().query(uri, projection, null, null, null);

    String contactName = "";

    if (cursor.moveToFirst()) 
    { 
        contactName = cursor.getString(0);
    }

    cursor.close();
    cursor = null;

    return contactName; 
}