如何编写一个接受二进制文件（pdf）的静态Web服务

Question

我试图用Java编写一个宁静的Web服务，该服务将包含一些字符串参数和一个二进制文件（pdf）参数。

我知道如何做字符串，但是我却挂在二进制文件上了。有什么想法/例子吗？

这是我到目前为止的

@GET
@ConsumeMime("multipart/form-data")
@ProduceMime("text/plain")
@Path("submit/{client_id}/{doc_id}/{html}/{password}")
public Response submit(@PathParam("client_id") String clientID,
                   @PathParam("doc_id") String docID,
                   @PathParam("html") String html,
                   @PathParam("password") String password,
                   @PathParam("pdf") File pdf) {
  return Response.ok("true").build();
}

由于我已经发布了此链接，因此删除了具有答案的链接，因此这是我的实现。

@POST
@Consumes(MediaType.MULTIPART_FORM_DATA)
@Produces(MediaType.TEXT_PLAIN)
@Path("submit")
public Response submit(@FormDataParam("clientID") String clientID,
                   @FormDataParam("html") String html,
                   @FormDataParam("pdf") InputStream pdfStream) {

    try {
        byte[] pdfByteArray = DocUtils.convertInputStreamToByteArrary(pdfStream);
    } catch (Exception ex) {
        return Response.status(600).entity(ex.getMessage()).build();
    }
}


...

public static byte[] convertInputStreamToByteArrary(InputStream in) throws IOException {
    ByteArrayOutputStream out = new ByteArrayOutputStream();
    final int BUF_SIZE = 1024;
    byte[] buffer = new byte[BUF_SIZE];
    int bytesRead = -1;
    while ((bytesRead = in.read(buffer)) > -1) {
        out.write(buffer, 0, bytesRead);
    }
    in.close();
    byte[] byteArray = out.toByteArray();
    return byteArray;
}

Answer 1

@POST
@Consumes(MediaType.MULTIPART_FORM_DATA)
@Produces(MediaType.TEXT_PLAIN)
@Path("submit")
public Response submit(@FormDataParam("clientID") String clientID,
                   @FormDataParam("html") String html,
                   @FormDataParam("pdf") InputStream pdfStream) {

    try {
        byte[] pdfByteArray = DocUtils.convertInputStreamToByteArrary(pdfStream);
    } catch (Exception ex) {
        return Response.status(600).entity(ex.getMessage()).build();
    }
}


...

public static byte[] convertInputStreamToByteArrary(InputStream in) throws IOException {
    ByteArrayOutputStream out = new ByteArrayOutputStream();
    final int BUF_SIZE = 1024;
    byte[] buffer = new byte[BUF_SIZE];
    int bytesRead = -1;
    while ((bytesRead = in.read(buffer)) > -1) {
        out.write(buffer, 0, bytesRead);
    }
    in.close();
    byte[] byteArray = out.toByteArray();
    return byteArray;
}