PHP中的JSON POST请求解析

Question

我已经在Java中生成了一个包含JSON对象的HTMLPost请求，并希望在PHP中对其进行解析。

public static String transferJSON(JSONObject j) {
    HttpClient httpclient= new DefaultHttpClient();
    HttpResponse response;
    HttpPost httppost= new HttpPost(SERVERURL);
    List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);  
    nameValuePairs.add(new BasicNameValuePair("json", j.toString()));

    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
    response = httpclient.execute(httppost);  
}

并在服务器上

<?php

if ($_SERVER['REQUEST_METHOD'] === 'POST') {

  // input = "json=%7B%22locations%22%3A%5B%7B%22..."
  $input = file_get_contents('php://input');

  // jsonObj is empty, not working
  $jsonObj = json_decode($input, true);

我猜这是因为JSON特殊字符已编码。

json_decode返回空响应

知道为什么吗？

Answer 1

实际上application/json，您不是在发布实体，而是在发布具有application/x-www-form- urlencoded单个值对json =（encoded json）的HTTP表单实体（）。

代替

List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);  
nameValuePairs.add(new BasicNameValuePair("json", j.toString()));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

尝试

 httppost.setEntity(new StringEntity(j.toString(),"application/json","UTF-8"));