因此,我使用apache
HttpComponents处理Java中的http请求。现在,我想重用DefaultHttpClient
,根据此示例,应该可以:http
://wiki.apache.org/HttpComponents/QuickStart
。该示例本身给出了ssl错误,因此我对其进行了简化和简化。现在我总是得到一个org.apache.http.client.ClientProtocolException
这是我的示例程序,基本上我只是使用相同的请求两个网页DefaultHttpClient
。
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.InputStream;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
public class ClientFormLogin {
public static void main(String[] args) throws Exception {
DefaultHttpClient httpclient = new DefaultHttpClient();
//Handle first request.
HttpGet httpget = new HttpGet("http://tweakers.net/nieuws/82969/amazon-nederland-opent-digitale-deuren-in-september.html");
HttpResponse response = httpclient.execute(httpget);
System.out.println("Execute finished");
HttpEntity entity = response.getEntity();
String page = readInput(entity.getContent());
System.out.println("Request one finished without problems!");
//Handle second request
HttpGet httpost = new HttpGet("http://gathering.tweakers.net/forum/list_messages/1506977/last");
response = httpclient.execute(httpost);
entity = response.getEntity();
page = readInput(entity.getContent());
System.out.println("Request two finished without problems!");
}
private static String readInput(InputStream in) throws IOException {
ByteArrayOutputStream out = new ByteArrayOutputStream();
byte bytes[] = new byte[1024];
int n = in.read(bytes);
while (n != -1) {
out.write(bytes, 0, n);
n = in.read(bytes);
}
return new String(out.toString());
}
}
在运行我的示例时,出现以下错误
Request one finished without problems!
Exception in thread "main" org.apache.http.client.ClientProtocolException
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:909)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:805)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:784)
at ClientFormLogin.main(ClientFormLogin.java:29)
Caused by: org.apache.http.HttpException: Unable to establish route: planned = {}->http://gathering.tweakers.net; current = {}->http://tweakers.net
at org.apache.http.impl.client.DefaultRequestDirector.establishRoute(DefaultRequestDirector.java:842)
at org.apache.http.impl.client.DefaultRequestDirector.tryConnect(DefaultRequestDirector.java:645)
at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:480)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:906)
... 3 more
任何人都可以给我一些指示,指出如何解决这个问题,但DefaultHttpClient
对于每个请求都使用一个新的指示符。
编辑
我只是发现如果我留在同一个域中就没有问题,所以:
page1: 'http://tweakers.net/nieuws/82969/amazon-nederland-opent-digitale-deuren-in-september.html'
page2: 'http://tweakers.net/nieuws/82973/website-nujij-belandt-op-zwarte-lijst-google-door-malware.html'
如果我要:
page1: 'http://tweakers.net/nieuws/82969/amazon-nederland-opent-digitale-deuren-in-september.html'
page2: 'http://gathering.tweakers.net/forum/list_messages/1506076/last'
我得到了错误。
我在发布问题后一分钟就看到了Ofc。除非有人可以告诉我我如何可以同时使用2个独立域名,否则DefaultHttpClient
我的问题已得到解答。
这可能是由于v4.2
BasicClientConnectionManager中的最新错误影响了跨站点重定向。参见http://issues.apache.org/jira/browse/HTTPCLIENT-1193。
根据维护者的说法,一种临时的解决方法是使用SingleClientConnManager或PoolingClientConnectionManager。也许是这样的:
ClientConnectionManager connManager = new PoolingClientConnectionManager();
DefaultHttpClient httpclient = new DefaultHttpClient(connManager);
...