从@UiThreadTest调用waitForMonitorWithTimeout（）

Question

为了说明我为Android应用编写JUnit测试的最新问题，我编写了一个简单示例，其中包含两个活动StartActivityForResult和ChildActivity。前者包含TextView（用于显示），Button而后者仅包含Button。中的onClickListenerfor按钮StartActivityForResult只是启动的实例ChildActivity。

private View.OnClickListener onStart = new View.OnClickListener() {
    @Override
    public void onClick(View view) {
        Log.d(TAG, "Start button clicked");
        Intent intent = new Intent(StartActivityForResult.this, ChildActivity.class);

        StartActivityForResult.this.startActivityForResult(intent, R.id.child_request);
    }
};

现在，我想使用JUnit测试此方法。所以我写了以下测试：

package codeguru.startactivityforresult;

import android.app.Activity;
import android.app.Instrumentation;
import android.content.Intent;
import android.test.ActivityInstrumentationTestCase2;
import android.test.UiThreadTest;
import android.util.Log;
import android.widget.Button;
import android.widget.TextView;
import junit.framework.Assert;

public class StartActivityForResultTest extends ActivityInstrumentationTestCase2<StartActivityForResult> {

    public StartActivityForResultTest() {
        super(StartActivityForResult.class);
    }

    @Override
    public void setUp() throws Exception {
        super.setUp();

        Log.d(TAG, "setUp()");

        this.setActivityInitialTouchMode(false);

        this.activity = this.getActivity();
        this.resultText = (TextView) this.activity.findViewById(R.id.result_text);
        this.startButton = (Button) this.activity.findViewById(R.id.start_button);

        Intent data = new Intent();
        data.putExtra(this.activity.getString(R.string.result), RESULT);
        Instrumentation.ActivityResult result = new Instrumentation.ActivityResult(Activity.RESULT_OK, data);

        this.childMonitor = new Instrumentation.ActivityMonitor(ChildActivity.class.getName(), result, true);
        this.getInstrumentation().addMonitor(this.childMonitor);
    }

    @Override
    public void tearDown() throws Exception {
        this.activity.finish();

        super.tearDown();
    }

    @UiThreadTest
    public void testStartButtonOnClick() {
        Assert.assertTrue(this.startButton.performClick());

        Activity childActivity = this.getInstrumentation().waitForMonitorWithTimeout(this.childMonitor, TIME_OUT);
        Assert.assertNotNull(childActivity); // <------ Line 51

        Button resultButton = (Button) childActivity.findViewById(R.id.result_button);
        Assert.assertTrue(resultButton.performClick());

        Assert.assertEquals(Integer.toString(RESULT), this.resultText.getText().toString());
    }
    private Activity activity = null;
    private TextView resultText = null;
    private Button startButton = null;
    private Instrumentation.ActivityMonitor childMonitor = null;
    private static final int TIME_OUT = 5 * 1000; // 5 seconds
    private static final int RESULT = 69;
    private static final String TAG = StartActivityForResultTest.class.getName();
}

运行此测试将给出以下输出：

codeguru@trolloc:~/src/java/stackoverflow/sscce/StartActivityForResult/test$ adb logcat -c
codeguru@trolloc:~/src/java/stackoverflow/sscce/StartActivityForResult/test$ adb shell am instrument -w -e class codeguru.startactivityforresult.StartActivityForResultTest codeguru.startactivityforresult.tests/android.test.InstrumentationTestRunner

codeguru.startactivityforresult.StartActivityForResultTest:
Failure in testStartButtonOnClick:
junit.framework.AssertionFailedError
    at codeguru.startactivityforresult.StartActivityForResultTest.testStartButtonOnClick(StartActivityForResultTest.java:51)
    at java.lang.reflect.Method.invokeNative(Native Method)
    at android.test.InstrumentationTestCase.runMethod(InstrumentationTestCase.java:214)
    at android.test.InstrumentationTestCase.access$000(InstrumentationTestCase.java:36)
    at android.test.InstrumentationTestCase$2.run(InstrumentationTestCase.java:189)
    at android.app.Instrumentation$SyncRunnable.run(Instrumentation.java:1602)
    at android.os.Handler.handleCallback(Handler.java:615)
    at android.os.Handler.dispatchMessage(Handler.java:92)
    at android.os.Looper.loop(Looper.java:137)
    at android.app.ActivityThread.main(ActivityThread.java:4745)
    at java.lang.reflect.Method.invokeNative(Native Method)
    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:786)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:553)
    at dalvik.system.NativeStart.main(Native Method)

Test results for InstrumentationTestRunner=.F
Time: 3.248

FAILURES!!!
Tests run: 1,  Failures: 1,  Errors: 0


codeguru@trolloc:~/src/java/stackoverflow/sscce/StartActivityForResult/test$ adb logcat -d codeguru.startactivityforresult.StartActivityForResultTest:D codeguru.startactivityforresult.StartActivityForResult:D codeguru.startactivityforresult.ChildActivity:D *:S
D/codeguru.startactivityforresult.StartActivityForResultTest(  954): setUp()
D/codeguru.startactivityforresult.StartActivityForResult(  954): onCreate()
D/codeguru.startactivityforresult.StartActivityForResult(  954): Start button clicked
layne@trolloc:~/src/java/stackoverflow/sscce/StartActivityForResult/test$

据我所知，调用startButton.performClick()不会启动的实例ChildActivity。是什么赋予了？

Answer 1

如对我的一个相关问题的回答所示，问题是我正在调用waitForMonitorWithTimeout()UI线程。意识到这一点之后，这肯定是完全有意义的，因为waitForMonitorWithTimeout()等待UI线程完成某些操作（即显示活动的UI）。但是，通过在UI线程上调用它，我延迟了该操作的发生。