Spring，Hibernate-多对多-LazyInitializationException

Question

我有2个模型。

用户：

    @Entity
public class User implements Serializable {
    Long id;
    String name;
    List<Car> cars;
    public User() {

    }
    public Long getId() {
        return id;
    }
    public void setId(Long id) {
        this.id = id;
    }
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public List<Car> getCars() {
        return cars;
    }
    public void setCars(List<Car> cars) {
        this.cars = cars;
    }
}

汽车：

@Entity
public class Car implements Serializable {
Long id;
String mark;
public Car() {

}
public Long getId() {
    return id;
}
public void setId(Long id) {
    this.id = id;
}
public String getMark() {
    return mark;
}
public void setMark(String mark) {
    this.mark = mark;
}
}

贴图：

用户：

    <hibernate-mapping>
<class name="com.bontade.phone_book.mvc.spring.models.User" table="USERS">
    <id name="id" type="java.lang.Long">
    <column name="ID" />
    <generator class="identity" />
    </id>        
    <property name="name" not-null="true" length="100" type="java.lang.String">
    <column name="NAME" />
    </property>       
    <list name="cars" table="USER_CAR" cascade="all">
    <key>
        <column name="USER_ID" />
    </key>
    <list-index></list-index>
    <many-to-many column="CAR_ID" class="com.bontade.phone_book.mvc.spring.models.Car" />
    </list>        
</class>
</hibernate-mapping>

汽车：

    <hibernate-mapping>
<class name="com.bontade.phone_book.mvc.spring.models.Car" table="CARS">
    <id name="id" type="java.lang.Long">
    <column name="ID" />
    <generator class="identity" />
    </id>
    <property name="mark"  not-null="true" length="20" type="java.lang.String">
    <column name="MARK" />
    </property>     
</class>
</hibernate-mapping>

HomePageController：

public class HomePageController extends AbstractController {
private UserDAO userDAO;
private CarDAO carDAO;

@Override
protected ModelAndView handleRequestInternal(HttpServletRequest request,
        HttpServletResponse response) throws Exception {        
    Car markCar = new Car();
    markCar.setId(null);
    markCar.setMark("111");
    carDAO.saveCar(markCar);

    User mark = new User();
    mark.setId(null);
    mark.setName("mark");
    List a = new ArrayList<Car>();
    a.add(markCar);
    mark.setCars(a);
    userDAO.saveUser(mark);
    List<User> users = userDAO.getAll();
    System.out.println("==" + users.size() + "===");
    System.out.println(users.get(0).getCars().get(0).getMark());

    ...
}
...
}

但是当我执行line时：

System.out.println(users.get(0).getCars().get(0).getMark());

以下堆栈跟踪出现错误：

        Hibernate: select user0_.ID as ID0_, user0_.NAME as NAME0_ from USERS user0_
==1==
2011-02-23 17:35:10 org.apache.catalina.core.StandardWrapperValve invoke
SEVERE: Servlet.service() for servlet [dispatcher] in context with path [/PhoneBook] threw exception [Request processing failed; nested exception is org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: com.bontade.phone_book.mvc.spring.models.User.cars, no session or session was closed] with root cause
org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: com.bontade.phone_book.mvc.spring.models.User.cars, no session or session was closed
    at org.hibernate.collection.AbstractPersistentCollection.throwLazyInitializationException(AbstractPersistentCollection.java:380)
    at org.hibernate.collection.AbstractPersistentCollection.throwLazyInitializationExceptionIfNotConnected(AbstractPersistentCollection.java:372)
    at org.hibernate.collection.AbstractPersistentCollection.readElementByIndex(AbstractPersistentCollection.java:173)
    at org.hibernate.collection.PersistentList.get(PersistentList.java:293)
    at com.bontade.phone_book.mvc.spring.controllers.HomePageController.handleRequestInternal(HomePageController.java:59)
    at org.springframework.web.servlet.mvc.AbstractController.handleRequest(AbstractController.java:153)
    at org.springframework.web.servlet.mvc.SimpleControllerHandlerAdapter.handle(SimpleControllerHandlerAdapter.java:48)
    at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:875)
    at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:807)
    at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:571)
    at org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:501)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:306)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
    at org.springframework.web.filter.CharacterEncodingFilter.doFilterInternal(CharacterEncodingFilter.java:96)
    at org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:76)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:244)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:240)
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:161)
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:164)
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:108)
    at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:558)
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:379)
    at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:243)
    at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:259)
    at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:281)
    at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908)
    at java.lang.Thread.run(Thread.java:662)

我是否构造了错误的映射文件，尤其是多对多关系？

Answer 1

默认情况下，Hibernate将延迟加载集合。换句话说，除非绝对需要，否则它不会进入数据库来检索汽车列表。这意味着从您的dao层返回的对象将不会初始化汽车列表，除非您尝试访问它。当您尝试访问它时，您就不再在会话中，因此您会获得异常。

您可以通过在hibernate映射中设置lazy =“ false”来显式禁用该list属性的延迟获取，这将确保在从dao层返回之前填充整个属性。