无法将java.lang.Integer字段设置为java.lang.Integer

Question

用户声明：

@Entity
public class User {
    @Id
    @GeneratedValue
    private Integer id;
    ....

模式声明：

@Entity
public class Pattern {
    @Id
    @GeneratedValue
    Integer id;
    ...

UserPatternDeclaration：

public class UserPattern {
    @Id
    @GeneratedValue
    Integer id;

    @ManyToOne
    @JoinColumn(name = "user_id")
    User user;

    @ManyToOne
    @JoinColumn(name = "pattern_id")
    Pattern pattern;
    ...

请求数据库：

Session session = sessionFactory.getCurrentSession();
Query query = session.createQuery("from UserPattern where user = :user_id and pattern = :pattern_id ");
query.setParameter("user_id", userId);
query.setParameter("pattern_id", pattern_id);
List<UserPattern> list = query.list();//exception throws here

我得到以下异常：

 ...
    java.lang.IllegalArgumentException: Can not set java.lang.Integer field 
    com.....s.model.User.id to java.lang.Integer
        at sun.reflect.UnsafeFieldAccessorImpl.throwSetIllegalArgumentException(UnsafeFieldAccessorImpl.java:164)
        at sun.reflect.UnsafeFieldAccessorImpl.throwSetIllegalArgumentException(UnsafeFieldAccessorImpl.java:168)
        at sun.reflect.UnsafeFieldAccessorImpl.ensureObj(UnsafeFieldAccessorImpl.java:55)
        at sun.reflect.UnsafeObjectFieldAccessorImpl.get(UnsafeObjectFieldAccessorImpl.java:36)
        at java.lang.reflect.Field.get(Field.java:379)
    ....

请帮助解决此问题。

错误消息看起来非常非常奇怪。

我已阅读相关主题的点击，但未找到答案。

ps

hibernate日志（异常之前）：

Hibernate: 
    select
        userpatter0_.id as id1_2_,
        userpatter0_.amountSearched as amountSe2_2_,
        userpatter0_.amountplayed as amountpl3_2_,
        userpatter0_.pattern_id as pattern_4_2_,
        userpatter0_.user_id as user_id5_2_ 
    from
        UserPattern userpatter0_ 
    where
        userpatter0_.user_id=? 
        and userpatter0_.pattern_id=?

在浏览器中，我看到以下消息：

HTTP Status 500....could not get a field value by reflection getter of...model.User.id

Answer 1

如果将HQL查询更改为会from UserPattern where user.id = :user_id and pattern.id = :pattern_id怎样？

我认为Hibernate混淆了对象和ID字段。