解析PostgreSQL TIMESTAMP类型的值时出现问题

Question

在PostgreSQL中，我有一个名为的表surveys。

CREATE TABLE SURVEYS(
  SURVEY_ID UUID PRIMARY KEY NOT NULL DEFAULT uuid_generate_v4(),
  SURVEY_NAME VARCHAR NOT NULL,
  SURVEY_DESCRIPTION TEXT,
  START_PERIOD TIMESTAMP,
  END_PERIOD TIMESTAMP
);

如您所见SURVEY_ID，SURVEY_NAME列为NOT NULL。

在Go中，我想通过POST请求在该表中创建新条目。我像这样发送JSON对象：

{
    "survey_name": "NAME",
    "survey_description": "DESCRIPTION",
    "start_period": "2019-01-01 00:00:00",
    "end_period": "2019-02-28 23:59:59"
}

不幸的是，它引发了奇怪的 错误 ：

parsing time ""2019-01-01 00:00:00"" as ""2006-01-02T15:04:05Z07:00"": cannot parse " 00:00:00"" as "T"

我在哪里犯错误以及如何解决我的问题？

models / surveys.go：

import (
    "database/sql"
    "time"
)

type NullTime struct {
    time.Time
    Valid bool
}

type Survey struct {
    ID int `json:"survey_id"`
    Name string `json:"survey_name"`
    Description sql.NullString `json:"survey_description"`
    StartPeriod NullTime `json:"start_period"`
    EndPeriod NullTime `json:"end_period"`
}

控制器/surveys.go：

var CreateSurvey = func(responseWriter http.ResponseWriter, request *http.Request) {
    // Initialize variables.
    survey := models.Survey{}
    var err error

    // The decoder introduces its own buffering and may read data from argument beyond the JSON values requested.
    err = json.NewDecoder(request.Body).Decode(&survey)
    if err != nil {
        log.Println(err)
        utils.ResponseWithError(responseWriter, http.StatusInternalServerError, err.Error())
        return
    }
    defer request.Body.Close()

    // Execute INSERT SQL statement.
    _, err = database.DB.Exec("INSERT INTO surveys (survey_name, survey_description, start_period, end_period) VALUES ($1, $2, $3, $4);", survey.Name, survey.Description, survey.StartPeriod, survey.EndPeriod)

    // Shape the response depending on the result of the previous command.
    if err != nil {
        log.Println(err)
        utils.ResponseWithError(responseWriter, http.StatusInternalServerError, err.Error())
        return
    }
    utils.ResponseWithSuccess(responseWriter, http.StatusCreated, "The new entry successfully created.")
}

Answer 1

该错误已说明出了什么问题：

将时间“” 2019-01-01 00:00:00“”解析为“” 2006-01-02T15：04：05Z07：00“”：无法将“
00:00:00”“解析为” T“

您正在传递，"2019-01-01 00:00:00"而它期望使用不同的时间格式，即RFC3339（UnmarshalJSON的默认值）。

为了解决这个问题，您要么希望以期望的格式传递时间，要么像这样"2019-01-01T00:00:00Z00:00"定义自己的类型CustomTime：

const timeFormat = "2006-01-02 15:04:05"

type CustomTime time.Time

func (ct *CustomTime) UnmarshalJSON(data []byte) error {
    newTime, err := time.Parse(timeFormat, strings.Trim(string(data), "\""))
    if err != nil {
        return err
    }

    *ct = CustomTime(newTime)
    return nil
}

func (ct *CustomTime) MarshalJSON() ([]byte, error) {
    return []byte(fmt.Sprintf("%q", time.Time(*ct).Format(timeFormat))), nil
}

小心，您可能还需要实现Valuer和Scanner接口，以便在数据库中进行解析时，如下所示：

func (ct CustomTime) Value() (driver.Value, error) {
    return time.Time(ct), nil
}

func (ct *CustomTime) Scan(src interface{}) error {
    if val, ok := src.(time.Time); ok {
        *ct = CustomTime(val)
    } else {
        return errors.New("time Scanner passed a non-time object")
    }

    return nil
}

转到Playground示例。