类型java.lang.String的值不能转换为JSONArray

Question

我花了2天的时间找到问题的解决方案。

这是错误：

E/log_tag: Error parsing data org.json.JSONException: Value of type java.lang.String cannot be converted to JSONArray

这是JSON：

[
{
    "Id": "5207fc6473516724343ce7a5",
    "Name": "Эриван",
    "Types": [
        "Ресторан"
    ],
    "Latitude": 53.904752,
    "Longitude": 27.521095,
    "OperatingTime": [
        {
            "Day": 1,
            "Start": "10:00:00",
            "Finish": "23:00:00"
        },
        {
            "Day": 2,
            "Start": "10:00:00",
            "Finish": "23:00:00"
        },
        {
            "Day": 3,
            "Start": "10:00:00",
            "Finish": "23:00:00"
        },
        {
            "Day": 4,
            "Start": "10:00:00",
            "Finish": "23:00:00"
        },
        {
            "Day": 5,
            "Start": "10:00:00",
            "Finish": "23:00:00"
        },
        {
            "Day": 6,
            "Start": "08:00:00",
            "Finish": "23:00:00"
        },
        {
            "Day": 0,
            "Start": "08:00:00",
            "Finish": "23:00:00"
        }
    ],
    "IsBookingAvailable": false
}]

用于获取字符串值的类：

 public class JSONGet {

    public static String getJSONfromURL(String url){
        InputStream is = null;
        String result = "";
        JSONArray jArray = null;

        // Download JSON data from URL
        try{
            HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost(url);
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();
            is = entity.getContent();

        }catch(Exception e){
            Log.e("log_tag", "Error in http connection "+e.toString());
        }

        // Convert response to string
        try{
            BufferedReader reader = new BufferedReader(new InputStreamReader(is,"UTF-8"),8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            result = sb.toString();
        }catch(Exception e){
            Log.e("log_tag", "Error converting result "+e.toString());
        }

        try{

            jArray = new JSONArray(result);
        }catch(JSONException e){
            Log.e("log_tag", "Error parsing data "+e.toString());
        }

        return result;
    }
  }

这是转换为JSONArray：

String jsonObjRecv = JSONGet.getJSONfromURL(URL_LIST);

JSONArray jsonArr = new JSONArray(jsonObjRecv);

我试图获取Json对象，然后将其转换为Json数组，但收到相同的错误。

Answer 1

问题是您的JSON格式不正确。我已经尝试过使用示例JSON，并找到了解决方案。现在，内置的JSONObject和JSONArray无法用于获取此类JSON响应。

您需要通过将其添加到gradle将json-simple库添加到您的项目中：

implementation 'com.googlecode.json-simple:json-simple:1.1.1'

或从此链接https://repo1.maven.org/maven2/com/googlecode/json-simple/json-
simple/1.1.1/json-simple-
下载链接库“ json-simple-1.1.1.jar”
1.1.1.jar

然后，您可以轻松解析JSON，并且不会出现任何错误。我为您制作了一个小示例代码，说明如何使用它：

import org.json.simple.JSONArray;
import org.json.simple.parser.JSONParser;

JSONParser parser_obj = new JSONParser();
JSONArray array_obj = (JSONArray) parser_obj.parse("String from web service"); 
// in your case it will be "result"

然后，您可以根据需要进行处理。