如何从子类调用基类的__init__方法？

Question

如果我有一个python类为：

class BaseClass(object):
#code and the init function of the base class

然后定义一个子类，例如：

class ChildClass(BaseClass):
#here I want to call the init function of the base class

如果基类的init函数接受某些参数，而我将它们作为子类的init函数的参数，则如何将这些参数传递给基类？

我写的代码是：

class Car(object):
    condition = "new"

    def __init__(self, model, color, mpg):
        self.model = model
        self.color = color
        self.mpg   = mpg

class ElectricCar(Car):
    def __init__(self, battery_type, model, color, mpg):
        self.battery_type=battery_type
        super(ElectricCar, self).__init__(model, color, mpg)

我要去哪里错了？

Answer 1

你可以用 super(ChildClass, self).__init__()

class BaseClass(object):
    def __init__(self, *args, **kwargs):
        pass

class ChildClass(BaseClass):
    def __init__(self, *args, **kwargs):
        super(ChildClass, self).__init__(*args, **kwargs)

您的缩进不正确，这是修改后的代码：

class Car(object):
    condition = "new"

    def __init__(self, model, color, mpg):
        self.model = model
        self.color = color
        self.mpg   = mpg

class ElectricCar(Car):
    def __init__(self, battery_type, model, color, mpg):
        self.battery_type=battery_type
        super(ElectricCar, self).__init__(model, color, mpg)

car = ElectricCar('battery', 'ford', 'golden', 10)
print car.__dict__

这是输出：

{'color': 'golden', 'mpg': 10, 'model': 'ford', 'battery_type': 'battery'}