我无法获得登录表单以正确连接与mySQL数据库的交互[关闭]

景远航

2023-03-14

问题内容：

关闭。 这个问题不能重现或由错别字引起。它当前不接受答案。

想改善这个问题吗？ 更新问题，使其成为Stack Overflow
的主题。

4年前关闭。

我想让用户使用用户名和密码登录，并且该数据是否与数据库中的用户名匹配。当我尝试时，我没有收到任何错误，但是没有用。我在Dreamweaver中使用html和php，在phpMyAdmin中使用WAM。我将同时包括表单文档和随附的php文档：

loginpage.php

 <?php
include('login.php'); // Includes Login Script

if(isset($_SESSION['login_user'])){
header("location: index.php");
}
?>

<table width="15px" border="0">
<form form action='login.php' method='POST'>
<tr>
<td>Username</td>
<td><input type="text" name="username" /></td>
</tr>
<tr>
<td>Password</td>
<td><input type="password" name="password" /></td>
</tr>
<tr>
  <td><input type="submit" name="submit" value="submit"/></td>
</tr>
</form>

  <html>
   <head>
    <title>Login</title>
  </head>
  <body>
  <?php 
    session_start(); // Starting Session
    $error=''; // Variable To Store Error Message
    if (isset($_POST['submit'])) {
    if (empty($_POST['username']) || empty($_POST['password'])) {
    $error = "Username or Password is invalid";
    }
    else
    {
    // Define $username and $password
    $username=$_POST['username'];
    $password=$_POST['password'];
    // Establishing Connection with Server by passing server_name, user_id   and password as a parameter
    $hostname= "localhost";
    $database = "boost";
    $username = "root";
    $password = "";
    $localhost = mysqli_connect($hostname, $username, $password, $database);
    if(mysqli_connect_errno())
    {
        die("Connection Failed".mysqli_error());
    }
    // SQL query to fetch information of registerd users and finds user match.
    $sql = "SELECT * FROM `users`";
    $query = mysqli_query($localhost,$sql);
    if(!$query)
    {
        die("Query Failed".mysqli_error($localhost));
    }
    $rows = mysqli_num_rows($query);
    if ($rows == 1) {
    $_SESSION['login_user']=$username; // Initializing Session
    echo "You are now logged on!";
    } else {
    $error = "Username or Password is invalid";
    }
    mysqli_close($localhost); // Closing Connection
    }
    }
  ?>
 </body>
 </html>

问题答案：

此答案适用于hashing，password_hash（）和password_verify（）。对于mysqli和pdo。底部的链接具有其他链接以及有关盐等的某些语言。

至关重要的是不要将用户提供的数据直接用于选择和插入。而是绑定参数并调用准备好的语句，以避免sql注入攻击。永远不要将密码以明文形式保存在数据库中。而是应通过单向哈希发送它们。

另请注意。这显示了注册哈希和登录验证。它 不是完整的 功能，我想花10美元在codecanyon上用…
…这样它表明电子邮件地址（登录名）的重新注册已经存在，确实更新了，请注意。在这种情况下，由于数据库中设置了唯一键，因此插入将完全失败。我将其留给读者（读者）进行查找，然后说“电子邮件已注册”。

架构图

CREATE TABLE `user_accounts2` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `email` varchar(100) NOT NULL,
  `password` varchar(255) NOT NULL,
  PRIMARY KEY (`id`),
  unique key(email) -- that better be the case
) ENGINE=InnoDB;

通过register.php运行并保存用户后，数据可能如下所示：

select * from user_accounts2;
+----+-----------+--------------------------------------------------------------+
| id | email     | password                                                     |
+----+-----------+--------------------------------------------------------------+
|  1 | d@d.com   | $2y$10$U6.WR.tiOIYNGDWddfT7kevJU8uiz8KAkdxXpda9e1xuplhC/eTJS |
+----+-----------+--------------------------------------------------------------+

mysqli部分第一

register.php

<?php
    mysqli_report(MYSQLI_REPORT_ALL);
    error_reporting(E_ALL); // report all PHP errors
    ini_set("display_errors", 1); // display them
    session_start();

    if(isset($_SESSION['userid'])!="") {
        // you are already logged in as session has been set
        header("Location: safe.php");   // note that this re-direct will at the top of that page
        // ... and there to verify the session state so no tricks can be performed
        // no tricks and gimmicks
    }

    if(isset($_POST['register'])) {
        $email = $_POST['email'];
        $ctPassword = $_POST['password'];   // cleartext password from user
        $hp=password_hash($ctPassword,PASSWORD_DEFAULT); // hashed password using cleartext one

        // pretend the following is locked in a vault and loaded but hard coded here
        $host="yourhostname";
        $dbname="dbname";
        $user="dbuser";
        $pwd="password";
        $port=3306; // comes along for the ride so I don't need to look up param order below
        // end pretend

        try {
            $mysqli= new mysqli($host, $user, $pwd, $dbname,$port);
            if ($mysqli->connect_error) {
                die('Connect Error (' . $mysqli->connect_errno . ') ' . $mysqli->connect_error);
            }
            //echo "I am connected and feel happy.<br/>";
            $query = "INSERT INTO user_accounts2(email,password) VALUES (?,?)";
            $stmt = $mysqli->prepare($query);

            // note the 2 s's below, s is for string
            $stmt->bind_param("ss", $email,$hp);    // never ever use non-sanitized user supplied data. Bind it
            $stmt->execute();
            // password is saved as hashed, will be verified on login page with password_verify()
            $iLastInsertId=$mysqli->insert_id;  // do something special with this (or not)
            // redirect to some login page (for now you just sit here)
            $stmt->close(); 
            $mysqli->close();
        } catch (mysqli_sql_exception $e) { 
            throw $e; 
        } 
    }
?>
<html>
<head>
<title>Register new user</title>
</head>
<body>
<div id="reg-form">
<form method="post">
    <table>
        <tr>
        <td><input type="email" name="email" placeholder="Email" required /></td>
        </tr>
        <tr>
        <td><input type="password" name="password" placeholder="Password" required /></td>
        </tr>
        <tr>
        <td><button type="submit" name="register">Register</button></td>
        </tr>
        <tr>
        <td><a href="index.php">Normal Login In Here</a></td>
        </tr>
    </table>
</form>
</div>
</body>
</html>

login.php

<?php
    mysqli_report(MYSQLI_REPORT_ALL);
    error_reporting(E_ALL); // report all PHP errors
    ini_set("display_errors", 1); // display them
    session_start();

    if(isset($_SESSION['userid'])!="") {
        // you are already logged in as session has been set
        header("Location: safe.php");   // note that this re-direct will at the top of that page
        // ... and there to verify the session state so no tricks can be performed
        // no tricks and gimmicks
    }

    if(isset($_POST['login'])) {
        $email = $_POST['email'];
        $ctPassword = $_POST['password'];   // cleartext password from user

        // pretend the following is locked in a vault and loaded but hard coded here
        $host="yourhostname";
        $dbname="dbname";
        $user="dbuser";
        $pwd="password";
        $port=3306; // comes along for the ride so I don't need to look up param order below
        // end pretend

        try {
            $mysqli= new mysqli($host, $user, $pwd, $dbname,$port);
            if ($mysqli->connect_error) {
                die('Connect Error (' . $mysqli->connect_errno . ') ' . $mysqli->connect_error);
            }
            //echo "I am connected and feel happy.<br/>";
            $query = "select id,email,password from user_accounts2 where email=?";
            $stmt = $mysqli->prepare($query);

            // note the "s" below, s is for string
            $stmt->bind_param("s", $email); // never ever use non-sanitized user supplied data. Bind it
            $stmt->execute();
            $result = $stmt->get_result();
            if ($row = $result->fetch_array(MYSQLI_ASSOC)) {
                $dbHashedPassword=$row['password'];
                if (password_verify($ctPassword,$dbHashedPassword)) {
                    echo "right, userid=";
                    $_SESSION['userid']=$row['id'];
                    echo $_SESSION['userid'];
                    // redirect to safe.php (note safeguards verbiage at top of this file about it)
                }
                else {
                    echo "wrong";
                    // could be overkill here, but in logout.php
                    // clear the $_SESSION['userid']
                }
            }
            else {
                echo 'no such record';
            }
            // remember, there is no iterating through rows, since there is 1 or 0 (email has a unique key)
            // also, hashes are one-way functions in the db. Once you hash and do the insert
            // there is pretty much no coming back to cleartext from the db with it. you just VERIFY it

            $stmt->close(); 
            $mysqli->close();
        } catch (mysqli_sql_exception $e) { 
            throw $e; 
        } 
    }
?>
<html>
<head>
<title>Login</title>
</head>
<body>
<div id="reg-form">
<form method="post">
    <table>
        <tr>
        <td><input type="email" name="email" placeholder="Email" required /></td>
        </tr>
        <tr>
        <td><input type="password" name="password" placeholder="Password" required /></td>
        </tr>
        <tr>
        <td><button type="submit" name="login">Login</button></td>
        </tr>
    </table>
</form>
</div>
</body>
</html>

下面的pdo部分

当我有时间时，大概是明天，但是现在我将您引向我的答案。

我无法获得登录表单以正确连接与mySQL数据库的交互[关闭]

架构图

register.php

login.php

相关阅读

相关文章

相关问答

相关工具

相关文档