SQL查询-多列的SUM（WHEN x THEN 1 ELSE 0的情况）

Question

我想看看下面是否有更好的查询方法。我想做的是创建一个摘要报告，按日期编译统计信息。

 SELECT CAST(Detail.ReceiptDate AS DATE) AS 'DATE'
, SUM(CASE WHEN Detail.Type = 'TotalMailed' THEN 1 ELSE 0 END) AS 'TOTALMAILED'
, SUM(CASE WHEN Detail.Type = 'TotalReturnMail' THEN 1 ELSE 0 END) AS 'TOTALUNDELINOTICESRECEIVED'
, SUM(CASE WHEN Detail.Type = 'TraceReturnedMail' THEN 1 ELSE 0 END) AS 'TRACEUNDELNOTICESRECEIVED'
FROM
(
select SentDate AS 'ReceiptDate', 'TotalMailed' AS 'Type'
from MailDataExtract
where sentdate is not null
UNION ALL
select MDE.ReturnMailDate AS 'ReceiptDate', 'TotalReturnMail' AS 'Type'
from MailDataExtract MDE
where MDE.ReturnMailDate is not null
UNION ALL
select MDE.ReturnMailDate AS 'ReceiptDate', 'TraceReturnedMail' AS 'Type'
from MailDataExtract MDE
    inner join DTSharedData.dbo.ScanData SD ON SD.ScanDataID = MDE.ReturnScanDataID
where MDE.ReturnMailDate is not null AND SD.ReturnMailTypeID = 1
) AS Detail
GROUP BY CAST(Detail.ReceiptDate AS DATE)
ORDER BY 1

这只是查询的一个示例（在报表中使用），因为还有许多其他列，并且其他统计信息的逻辑更加复杂。是否有更优雅的方法来获取此类信息/撰写此类报告？

Answer 1

我将通过以下方式更改查询：

1. 在子查询中进行聚合。这样可以利用有关表格的更多信息来优化group by。
2. 合并第二个和第三个子查询。它们聚集在同一列上。这需要使用left outer join来确保所有数据都可用。
3. 通过使用，count(<fieldname>)您可以消除与的比较is null。这对于第二和第三计算值很重要。
4. 要组合第二个查询和第三个查询，它需要从mde表中计算一个ID 。这些使用mde.mdeid。

以下版本通过使用来遵循您的示例union all：

SELECT CAST(Detail.ReceiptDate AS DATE) AS "Date",
       SUM(TOTALMAILED) as TotalMailed,
       SUM(TOTALUNDELINOTICESRECEIVED) as TOTALUNDELINOTICESRECEIVED,
       SUM(TRACEUNDELNOTICESRECEIVED) as TRACEUNDELNOTICESRECEIVED
FROM ((select SentDate AS "ReceiptDate", COUNT(*) as TotalMailed,
              NULL as TOTALUNDELINOTICESRECEIVED, NULL as TRACEUNDELNOTICESRECEIVED
       from MailDataExtract
       where SentDate is not null
       group by SentDate
      ) union all
      (select MDE.ReturnMailDate AS ReceiptDate, 0,
              COUNT(distinct mde.mdeid) as TOTALUNDELINOTICESRECEIVED,
              SUM(case when sd.ReturnMailTypeId = 1 then 1 else 0 end) as TRACEUNDELNOTICESRECEIVED
       from MailDataExtract MDE left outer join
            DTSharedData.dbo.ScanData SD
            ON SD.ScanDataID = MDE.ReturnScanDataID
       group by MDE.ReturnMailDate;
      )
     ) detail
GROUP BY CAST(Detail.ReceiptDate AS DATE)
ORDER BY 1;

以下使用做了类似的事情full outer join：

SELECT coalesce(sd.ReceiptDate, mde.ReceiptDate) AS "Date",
       sd.TotalMailed, mde.TOTALUNDELINOTICESRECEIVED,
       mde.TRACEUNDELNOTICESRECEIVED
FROM (select cast(SentDate as date) AS "ReceiptDate", COUNT(*) as TotalMailed
      from MailDataExtract
      where SentDate is not null
      group by cast(SentDate as date)
     ) sd full outer join
    (select cast(MDE.ReturnMailDate as date) AS ReceiptDate,
            COUNT(distinct mde.mdeID) as TOTALUNDELINOTICESRECEIVED,
            SUM(case when sd.ReturnMailTypeId = 1 then 1 else 0 end) as TRACEUNDELNOTICESRECEIVED
     from MailDataExtract MDE left outer join
          DTSharedData.dbo.ScanData SD
          ON SD.ScanDataID = MDE.ReturnScanDataID
     group by cast(MDE.ReturnMailDate as date)
    ) mde
    on sd.ReceiptDate = mde.ReceiptDate
ORDER BY 1;