在Beautifulsoup Python上排除不需要的标签

Question

<span>
  I Like
  <span class='unwanted'> to punch </span>
   your face
 </span>

如何打印“我喜欢你的脸”而不是“我喜欢打你的脸”

我试过了

lala = soup.find_all('span')
for p in lala:
 if not p.find(class_='unwanted'):
    print p.text

但它给出“ TypeError：find（）不包含关键字参数”

Answer 1

您可以extract()先删除不需要的标签，然后再获取文字。

但是它保留了所有内容'\n'，spaces因此您需要一些工作才能删除它们。

data = '''<span>
  I Like
  <span class='unwanted'> to punch </span>
   your face
 <span>'''

from bs4 import BeautifulSoup as BS

soup = BS(data, 'html.parser')

external_span = soup.find('span')

print("1 HTML:", external_span)
print("1 TEXT:", external_span.text.strip())

unwanted = external_span.find('span')
unwanted.extract()

print("2 HTML:", external_span)
print("2 TEXT:", external_span.text.strip())

结果

1 HTML: <span>
  I Like
  <span class="unwanted"> to punch </span>
   your face
 <span></span></span>
1 TEXT: I Like
   to punch 
   your face
2 HTML: <span>
  I Like

   your face
 <span></span></span>
2 TEXT: I Like

   your face

您可以跳过Tag外部范围内的每个对象，而仅保留NavigableString对象（HTML中为纯文本）。

data = '''<span>
  I Like
  <span class='unwanted'> to punch </span>
   your face
 <span>'''

from bs4 import BeautifulSoup as BS
import bs4

soup = BS(data, 'html.parser')

external_span = soup.find('span')

text = []
for x in external_span:
    if isinstance(x, bs4.element.NavigableString):
        text.append(x.strip())
print(" ".join(text))

结果

I Like your face