在node.js中“需要”后如何删除模块？

Question

假设我需要一个模块并执行以下操作：

var b = require('./b.js');
--- do something with b ---

然后，我要拿走模块b（即清理缓存）。我该怎么办？

原因是我想动态加载/删除或更新模块，而无需重新启动节点服务器。任何想法？

-------更多--------根据删除require.cache的建议，它仍然不起作用…

what I did are few things:
1) delete require.cache[require.resolve('./b.js')];
2) loop for every require.cache's children and remove any child who is b.js
3) delete b

但是，当我呼叫b时，它仍然存在！它仍然可以访问。除非我这样做：

b = {};

不知道这是否是处理该问题的好方法。因为如果以后再修改b.js，我又需要（’./b.js’）。它需要旧的缓存b.js（我尝试删除）还是新的？

-----------更多发现--------------

好。我进行了更多的测试，并尝试了代码。.这是我发现的：

1) delete require.cache[]  is essential.  Only if it is deleted, 
 then the next time I load a new b.js will take effect.
2) looping through require.cache[] and delete any entry in the 
 children with the full filename of b.js doesn't take any effect.  i.e.
u can delete or leave it.  However, I'm unsure if there is any side
effect.  I think it is a good idea to keep it clean and delete it if
there is no performance impact.
3) of course, assign b={} doesn't really necessary, but i think it is 
 useful to also keep it clean.

Answer 1

您可以使用此命令在缓存中删除其条目：

delete require.cache[require.resolve('./b.js')]

require.resolve()将找出的完整路径./b.js，该路径用作缓存键。