从sequelize.js中的关联模型加载属性

Question

我有两个模型。用户和管理员

用户模型

 const UserMaster = sequelize.define('User', {
        UserId: {
            type: DataTypes.BIGINT,
            allowNull: false,
            primaryKey: true,
            autoIncrement: true
        },
        RelationshipId: {
            type: DataTypes.STRING,
            allowNull: true,
            foreignKey: true
        },
        UserName: {
            type: DataTypes.STRING,
            allowNull: true
        }
    })

经理模式

 const Manager = sequelize.define('Manager', {
        ManagerId: {
            type: DataTypes.BIGINT,
            allowNull: false,
            primaryKey: true,
            autoIncrement: true
        },
        RelationshipId: {
            type: DataTypes.STRING,
            allowNull: true,
            foreignKey: true
        },
        MangerName: {
            type: DataTypes.STRING,
            allowNull: true
        }
    })

缩小模型以简单地解决问题

协会..

User.belongsTo(models.Manager, {
    foreignKey: 'RelationshipId',
    as: 'RM'
});

Manger.hasMany(model.User, {
    foreignKey: 'RelationshipId',
    as: "Users"
})

因此，在user.findAll（）上

var userObject = models.User.findAll({
    include: [{
        model: models.Manager,
        required: false,
        as: 'RM',
        attributes: ['ManagerName']
    }]
});

我得到以下内容。

userObject = [{
        UserId: 1,
        RelationshipId: 4545,
        UserName: 'Jon',
        RM: {
            ManagerName: 'Sam'
        }
    },
    {
        UserId: 2,
        RelationshipId: 432,
        UserName: 'Jack',
        RM: {
            ManagerName: 'Phil'
        }
    },
    ...
]

如何将’ManagerName’属性从Manager模型（关联为RM）移动到UserObject？是否可以以某种方式从急切加载的模型中加载属性，而无需将它们嵌套在单独的对象下？我希望得到的对象看起来像对象

预期对象-

userObject = [{
        UserId: 1,
        RelationshipId: 4545,
        UserName: 'Jon',
        ManagerName: 'Sam' // <-- from Manager model
    },
    {
        UserId: 2,
        RelationshipId: 432,
        UserName: 'Jack',
        ManagerName: 'Phil' // <-- from Manager model
    },
    ...
]

谢谢你。

Answer 1

raw: true与attributesoption一起添加可以得到所需的对象格式。

所以，

var userObject = models.User.findAll({
raw:true,
attributes: {
include: [Sequelize.col('RM.ManagerName'), 'ManagerName']
},
    include: [{
        model: models.Manager,
        required: false,
        as: 'RM',
        attributes: []
    }]
});