是否可以使用SQL将身份添加到GROUP BY？

Question

是否可以在GROUP BY中添加一个标识列，以便每个重复项都有一个标识号？

我的原始数据如下所示：

1    AAA  [timestamp]
2    AAA  [timestamp]
3    BBB  [timestamp]
4    CCC  [timestamp]
5    CCC  [timestamp]
6    CCC  [timestamp]
7    DDD  [timestamp]
8    DDD  [timestamp]
9    EEE  [timestamp]
....

我想将其转换为：

1    AAA   1
2    AAA   2
4    CCC   1
5    CCC   2
6    CCC   3
7    DDD   1
8    DDD   2
...

解决方案是：

CREATE PROCEDURE [dbo].[RankIt]
AS
BEGIN
SET NOCOUNT ON;

SELECT  *, RANK() OVER(PARTITION BY col2 ORDER BY timestamp DESC) AS ranking 
FROM MYTABLE;

END

Answer 1

如果您使用的是Sql Server 2005，则可以尝试使用ROW_NUMBER

DECLARE @Table TABLE(
        ID INT,
        Val VARCHAR(10)
)

INSERT INTO @Table SELECT 1,'AAA'
INSERT INTO @Table SELECT 2,'AAA'
INSERT INTO @Table SELECT 3,'BBB' 
INSERT INTO @Table SELECT 4,'CCC' 
INSERT INTO @Table SELECT 5,'CCC' 
INSERT INTO @Table SELECT 6,'CCC' 
INSERT INTO @Table SELECT 7,'DDD' 
INSERT INTO @Table SELECT 8,'DDD' 
INSERT INTO @Table SELECT 9,'EEE'

SELECT  *,
        ROW_NUMBER() OVER(PARTITION BY VAL ORDER BY Val)
FROM    @Table