生成名词的复数形式

Question

给定一个单词，该单词可能是也可能不是单数形式的名词，您将如何生成其复数形式？

基于这个NLTK教程和这个关于复数规则的非正式列表，我编写了这个简单的函数：

def plural(word):
    """
    Converts a word to its plural form.
    """
    if word in c.PLURALE_TANTUMS:
        # defective nouns, fish, deer, etc
        return word
    elif word in c.IRREGULAR_NOUNS:
        # foot->feet, person->people, etc
        return c.IRREGULAR_NOUNS[word]
    elif word.endswith('fe'):
        # wolf -> wolves
        return word[:-2] + 'ves'
    elif word.endswith('f'):
        # knife -> knives
        return word[:-1] + 'ves'
    elif word.endswith('o'):
        # potato -> potatoes
        return word + 'es'
    elif word.endswith('us'):
        # cactus -> cacti
        return word[:-2] + 'i'
    elif word.endswith('on'):
        # criterion -> criteria
        return word[:-2] + 'a'
    elif word.endswith('y'):
        # community -> communities
        return word[:-1] + 'ies'
    elif word[-1] in 'sx' or word[-2:] in ['sh', 'ch']:
        return word + 'es'
    elif word.endswith('an'):
        return word[:-2] + 'en'
    else:
        return word + 's'

但是我认为这是不完整的。有一个更好的方法吗？

Answer 1

pattern-en软件包（适用于python 2.5+，但不适用于python
3）提供了复数形式

>>> import pattern.en
>>> pattern.en.pluralize("dog")
'dogs'
>>>